A charge of 5 10^-9 C is placed in an electric field of 2 10^5 N/C. The force on it is:

  1. 0.002 N
  2. 0.01 N
  3. 1 10^-4 N
  4. 0.001 N
Answer

D) 0.001 N

F = qE = 5 10^-9 2 10^5 = 0.001 N. SLO P-11-E-02 · Application

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