A charge of 3 10^-6 C is placed in an electric field of 400 N/C. The force on it is:

  1. 0.0024 N
  2. 0.012 N
  3. 0.0012 N
  4. 1.2 10^-4 N
Answer

C) 0.0012 N

F = qE = 3 10^-6 400 = 0.0012 N. SLO P-11-E-02 · Application

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