26. A student scores 80, 70, 90 in subjects with credit hours 3, 2, 1. The weighted mean score is:
- 75.33
- 80.83
- 78.33
- 80
Answer: C) 78.33
Explanation: barxw = sum wxsum w = 4706 = 78.33. SLO M-09-C-03 · Application
MCQs / Mathematics / Measures of Central Tendency
44 multiple-choice questions on Measures of Central Tendency from Mathematics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.
Answer: C) 78.33
Explanation: barxw = sum wxsum w = 4706 = 78.33. SLO M-09-C-03 · Application
Answer: A) 70
Explanation: Total = 5 75 = 375; missing = 375 - 305 = 70. SLO M-09-C-03 · Application
Answer: C) 20–30
Explanation: The modal class has the highest frequency (10). SLO M-09-C-02 · Understanding
Answer: B) 124
Explanation: n = 60, n2 = 30. The median class is 120 –130 with l = 120, h = 10, f = 20, c = 22. Median = 120 + 1020(30 - 22) = 124. SLO M-09-C-02 · Understanding
Answer: A) 50.8
Explanation: Using midpoints x: sum fx = 2540, sum f = 50, so barx = sum fxsum f = 50.8. SLO M-09-C-02 · Understanding
Answer: C) the mean
Explanation: The mean adds every value. SLO M-09-C-03 · Application
Answer: B) 64
Explanation: Using midpoints x: sum fx = 2560, sum f = 40, so barx = sum fxsum f = 64. SLO M-09-C-02 · Understanding
Answer: C) 30–35
Explanation: The modal class has the highest frequency (14). SLO M-09-C-02 · Understanding
Answer: D) 19
Explanation: Total = 4 16 = 64; missing = 64 - 45 = 19. SLO M-09-C-03 · Application
Answer: A) 25
Explanation: n = 30, n2 = 15. The median class is 20 –30 with l = 20, h = 10, f = 10, c = 10. Median = 20 + 1010(15 - 10) = 25. SLO M-09-C-02 · Understanding
Answer: A) 7
Explanation: 7 appears most often. SLO M-09-C-03 · Application
Answer: A) the median
Explanation: One extreme value pulls the mean up a lot; the median is not affected by it. SLO M-09-C-03 · Application
Answer: A) 33.25
Explanation: Using midpoints x: sum fx = 1330, sum f = 40, so barx = sum fxsum f = 33.25. SLO M-09-C-02 · Understanding
Answer: C) 14 mm
Explanation: 705 = 14 mm. SLO M-09-C-03 · Application
Answer: D) ( n2 ) th value
Explanation: Use the cumulative frequencies to find where the n2th value falls. SLO M-09-C-02 · Understanding
Answer: D) 35.75
Explanation: Using midpoints x: sum fx = 1430, sum f = 40, so barx = sum fxsum f = 35.75. SLO M-09-C-02 · Understanding
Answer: C) highest frequency
Explanation: Mode = most frequent. SLO M-09-C-02 · Understanding
Answer: C) an estimate
Explanation: The actual values inside each class are not known. SLO M-09-C-02 · Understanding
Answer: D) 63.33
Explanation: n = 40, n2 = 20. The median class is 60 –70 with l = 60, h = 10, f = 15, c = 15. Median = 60 + 1015(20 - 15) = 63.33. SLO M-09-C-02 · Understanding
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Practise Measures of Central Tendency MCQs