MCQs / Physics / Current Electricity
Current Electricity MCQs — Physics (page 6) 270 multiple-choice questions on Current Electricity from Physics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.
126. A typical use of an LDR is: a fuse a loudspeaker automatic street lights a heating element Answer: C) automatic street lights
Explanation: Senses darkness. SLO P-09-E-14 · Knowledge
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127. A wire has resistivity 1.7 10^-8 Ω m, length 10 m and cross-section 1 10^-6 m^2. Its resistance is: 0.34 Ω 0.17 Ω 1.7 Ω 0.017 Ω Answer: B) 0.17 Ω
Explanation: R = rho LA = 0.17 Ω. SLO P-09-E-13 · Application
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128. The drift velocity of electrons in a typical wire is: about 1 km/s less than a millimetre per second about 300 m/s about the speed of light Answer: B) less than a millimetre per second
Explanation: Very slow. SLO P-09-E-10 · Application
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129. A device draws 0.5 A from a 230 V supply. Its power is: 460 W 115 W 57.5 W 230 W Answer: B) 115 W
Explanation: P = IV = 115 W. SLO P-09-E-12 · Application
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130. The reading of a galvanometer at the null point is independent of its resistance because: no current flows through it the current is very large it has zero resistance it is in parallel Answer: A) no current flows through it
Explanation: No p.d. across it. SLO P-09-E-24 · Understanding
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131. In terms of energy, the 'lost volts' inside a cell represent: energy gained by the cell energy wasted as heat in the internal resistance energy given to the lamp energy stored in the wires Answer: B) energy wasted as heat in the internal resistance
Explanation: Ir. SLO P-09-E-16 · Understanding
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132. A source of e.m.f. 12 V drives 2 A for 30 s. The energy it supplies is: 720 J 1440 J 24 J 360 J Answer: A) 720 J
Explanation: W = mathcalEIt = 720 J. SLO P-09-E-15 · Application
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133. When applying Kirchhoff's second law to a loop, you must: include every e.m.f. and IR term around the loop with correct signs add all currents ignore resistors include only the batteries Answer: A) include every e.m.f. and IR term around the loop with correct signs
Explanation: Sign conventions matter. SLO P-09-E-22 · Application
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134. Energy wasted inside a battery due to its internal resistance appears as: heat in the battery light extra e.m.f. sound Answer: A) heat in the battery
Explanation: I^2r. SLO P-09-E-26 · Understanding
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135. Three identical 1.5 V cells in parallel give an e.m.f. of: 1.5 V 0.5 V 3.0 V 4.5 V Answer: A) 1.5 V
Explanation: Parallel cells keep the same e.m.f. SLO P-09-E-15 · Application
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136. A high resistance is often placed in series with the galvanometer at first to: make it read zero reverse the current protect it while finding the approximate balance point increase its sensitivity Answer: C) protect it while finding the approximate balance point
Explanation: Removed for final balance. SLO P-09-E-24 · Understanding
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137. Which graph shows the behaviour of an LDR? resistance falling as light intensity rises resistance rising with light resistance rising with temperature a horizontal line Answer: A) resistance falling as light intensity rises
Explanation: Inverse relationship (non-linear). SLO P-09-E-14 · Knowledge
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138. The SI unit of resistivity is: Ω Ω m^2 Ω m Ω/m Answer: C) Ω m
Explanation: rho = RA/L. SLO P-09-E-13 · Application
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139. A current of 2 A flows in a wire with n = 8.5 10^28 m^-3 and area 1 10^-6 m^2. The drift velocity of the electrons is: 1.47 10^-4 m/s 1.47 10^-5 m/s 0.00147 m/s 2.94 10^-4 m/s Answer: A) 1.47 10^-4 m/s
Explanation: v = InAq = 1.47 10^-4 m/s — very slow. SLO P-09-E-10 · Application
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140. A 46 Ω resistor is connected to 230 V. The power is: 1150 W 5 W 2300 W 10,600 W Answer: A) 1150 W
Explanation: P = V^2R = 230^246 = 1150 W. SLO P-09-E-12 · Application
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141. Three 1.5 V cells in series have a total e.m.f. of: 1.5 V 4.5 V 3.0 V 0.5 V Answer: B) 4.5 V
Explanation: e.m.f.s add in series. SLO P-09-E-15 · Application
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142. For a load much larger than the internal resistance, the terminal p.d. is: twice the e.m.f. almost equal to the e.m.f. almost zero half the e.m.f. Answer: B) almost equal to the e.m.f.
Explanation: Small current, few lost volts. SLO P-09-E-26 · Understanding
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143. Kirchhoff's first law is a consequence of the conservation of: mass energy charge momentum Answer: C) charge
Explanation: Charge can't pile up at a junction. SLO P-09-E-18 · Knowledge
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144. A coulomb of charge going once round a circuit with a 6 V battery loses in the components a total energy of: 12 J 3 J 6 J 0 J Answer: C) 6 J
Explanation: Energy given = energy used. SLO P-09-E-19 · Understanding
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145. Resistors of 1.5 Ω, 2.5 Ω, 6 Ω are connected in series. The combined resistance is: 10 Ω 5 Ω 20 Ω 100 Ω Answer: A) 10 Ω
Explanation: R = R1 + R2 + ldots = 10 Ω. SLO P-09-E-20 · Application
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146. A charge of 40 C moves through a p.d. of 1.5 V. The energy transferred is: 60 J 120 J 30 J 0.0375 J Answer: A) 60 J
Explanation: W = QV = 60 J. SLO P-09-E-11 · Application
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147. A potential divider works by: storing charge changing the e.m.f. sharing the supply p.d. between resistors in proportion to their resistances adding current Answer: C) sharing the supply p.d. between resistors in proportion to their resistances
Explanation: Series resistors share p.d. SLO P-09-E-25 · Understanding
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148. Kirchhoff's second law states that around any closed loop: the sum of the e.m.f.s equals the sum of the p.d.s (IR terms) the resistance is zero the current is the same the sum of the currents is zero Answer: A) the sum of the e.m.f.s equals the sum of the p.d.s (IR terms)
Explanation: Voltage (loop) law. SLO P-09-E-19 · Understanding
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149. In the loop above, the p.d. across the 4 Ω resistor is: 2 V 12 V 8 V 4 V Answer: C) 8 V
Explanation: V = IR = 2 4. SLO P-09-E-19 · Understanding
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150. Three identical lamps in parallel draw 0.6 A in total. Each lamp carries: 0.2 A 1.8 A 0.6 A 0.3 A Answer: A) 0.2 A
Explanation: Current splits equally. SLO P-09-E-18 · Knowledge
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