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Current Electricity MCQs — Physics (page 6)

270 multiple-choice questions on Current Electricity from Physics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.

126. A typical use of an LDR is:

  1. a fuse
  2. a loudspeaker
  3. automatic street lights
  4. a heating element

Answer: C) automatic street lights

Explanation: Senses darkness. SLO P-09-E-14 · Knowledge

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127. A wire has resistivity 1.7 10^-8 Ω m, length 10 m and cross-section 1 10^-6 m^2. Its resistance is:

  1. 0.34 Ω
  2. 0.17 Ω
  3. 1.7 Ω
  4. 0.017 Ω

Answer: B) 0.17 Ω

Explanation: R = rho LA = 0.17 Ω. SLO P-09-E-13 · Application

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128. The drift velocity of electrons in a typical wire is:

  1. about 1 km/s
  2. less than a millimetre per second
  3. about 300 m/s
  4. about the speed of light

Answer: B) less than a millimetre per second

Explanation: Very slow. SLO P-09-E-10 · Application

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129. A device draws 0.5 A from a 230 V supply. Its power is:

  1. 460 W
  2. 115 W
  3. 57.5 W
  4. 230 W

Answer: B) 115 W

Explanation: P = IV = 115 W. SLO P-09-E-12 · Application

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130. The reading of a galvanometer at the null point is independent of its resistance because:

  1. no current flows through it
  2. the current is very large
  3. it has zero resistance
  4. it is in parallel

Answer: A) no current flows through it

Explanation: No p.d. across it. SLO P-09-E-24 · Understanding

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131. In terms of energy, the 'lost volts' inside a cell represent:

  1. energy gained by the cell
  2. energy wasted as heat in the internal resistance
  3. energy given to the lamp
  4. energy stored in the wires

Answer: B) energy wasted as heat in the internal resistance

Explanation: Ir. SLO P-09-E-16 · Understanding

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132. A source of e.m.f. 12 V drives 2 A for 30 s. The energy it supplies is:

  1. 720 J
  2. 1440 J
  3. 24 J
  4. 360 J

Answer: A) 720 J

Explanation: W = mathcalEIt = 720 J. SLO P-09-E-15 · Application

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133. When applying Kirchhoff's second law to a loop, you must:

  1. include every e.m.f. and IR term around the loop with correct signs
  2. add all currents
  3. ignore resistors
  4. include only the batteries

Answer: A) include every e.m.f. and IR term around the loop with correct signs

Explanation: Sign conventions matter. SLO P-09-E-22 · Application

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134. Energy wasted inside a battery due to its internal resistance appears as:

  1. heat in the battery
  2. light
  3. extra e.m.f.
  4. sound

Answer: A) heat in the battery

Explanation: I^2r. SLO P-09-E-26 · Understanding

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135. Three identical 1.5 V cells in parallel give an e.m.f. of:

  1. 1.5 V
  2. 0.5 V
  3. 3.0 V
  4. 4.5 V

Answer: A) 1.5 V

Explanation: Parallel cells keep the same e.m.f. SLO P-09-E-15 · Application

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136. A high resistance is often placed in series with the galvanometer at first to:

  1. make it read zero
  2. reverse the current
  3. protect it while finding the approximate balance point
  4. increase its sensitivity

Answer: C) protect it while finding the approximate balance point

Explanation: Removed for final balance. SLO P-09-E-24 · Understanding

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137. Which graph shows the behaviour of an LDR?

  1. resistance falling as light intensity rises
  2. resistance rising with light
  3. resistance rising with temperature
  4. a horizontal line

Answer: A) resistance falling as light intensity rises

Explanation: Inverse relationship (non-linear). SLO P-09-E-14 · Knowledge

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138. The SI unit of resistivity is:

  1. Ω
  2. Ω m^2
  3. Ω m
  4. Ω/m

Answer: C) Ω m

Explanation: rho = RA/L. SLO P-09-E-13 · Application

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139. A current of 2 A flows in a wire with n = 8.5 10^28 m^-3 and area 1 10^-6 m^2. The drift velocity of the electrons is:

  1. 1.47 10^-4 m/s
  2. 1.47 10^-5 m/s
  3. 0.00147 m/s
  4. 2.94 10^-4 m/s

Answer: A) 1.47 10^-4 m/s

Explanation: v = InAq = 1.47 10^-4 m/s — very slow. SLO P-09-E-10 · Application

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140. A 46 Ω resistor is connected to 230 V. The power is:

  1. 1150 W
  2. 5 W
  3. 2300 W
  4. 10,600 W

Answer: A) 1150 W

Explanation: P = V^2R = 230^246 = 1150 W. SLO P-09-E-12 · Application

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141. Three 1.5 V cells in series have a total e.m.f. of:

  1. 1.5 V
  2. 4.5 V
  3. 3.0 V
  4. 0.5 V

Answer: B) 4.5 V

Explanation: e.m.f.s add in series. SLO P-09-E-15 · Application

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142. For a load much larger than the internal resistance, the terminal p.d. is:

  1. twice the e.m.f.
  2. almost equal to the e.m.f.
  3. almost zero
  4. half the e.m.f.

Answer: B) almost equal to the e.m.f.

Explanation: Small current, few lost volts. SLO P-09-E-26 · Understanding

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143. Kirchhoff's first law is a consequence of the conservation of:

  1. mass
  2. energy
  3. charge
  4. momentum

Answer: C) charge

Explanation: Charge can't pile up at a junction. SLO P-09-E-18 · Knowledge

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144. A coulomb of charge going once round a circuit with a 6 V battery loses in the components a total energy of:

  1. 12 J
  2. 3 J
  3. 6 J
  4. 0 J

Answer: C) 6 J

Explanation: Energy given = energy used. SLO P-09-E-19 · Understanding

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145. Resistors of 1.5 Ω, 2.5 Ω, 6 Ω are connected in series. The combined resistance is:

  1. 10 Ω
  2. 5 Ω
  3. 20 Ω
  4. 100 Ω

Answer: A) 10 Ω

Explanation: R = R1 + R2 + ldots = 10 Ω. SLO P-09-E-20 · Application

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146. A charge of 40 C moves through a p.d. of 1.5 V. The energy transferred is:

  1. 60 J
  2. 120 J
  3. 30 J
  4. 0.0375 J

Answer: A) 60 J

Explanation: W = QV = 60 J. SLO P-09-E-11 · Application

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147. A potential divider works by:

  1. storing charge
  2. changing the e.m.f.
  3. sharing the supply p.d. between resistors in proportion to their resistances
  4. adding current

Answer: C) sharing the supply p.d. between resistors in proportion to their resistances

Explanation: Series resistors share p.d. SLO P-09-E-25 · Understanding

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148. Kirchhoff's second law states that around any closed loop:

  1. the sum of the e.m.f.s equals the sum of the p.d.s (IR terms)
  2. the resistance is zero
  3. the current is the same
  4. the sum of the currents is zero

Answer: A) the sum of the e.m.f.s equals the sum of the p.d.s (IR terms)

Explanation: Voltage (loop) law. SLO P-09-E-19 · Understanding

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149. In the loop above, the p.d. across the 4 Ω resistor is:

  1. 2 V
  2. 12 V
  3. 8 V
  4. 4 V

Answer: C) 8 V

Explanation: V = IR = 2 4. SLO P-09-E-19 · Understanding

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150. Three identical lamps in parallel draw 0.6 A in total. Each lamp carries:

  1. 0.2 A
  2. 1.8 A
  3. 0.6 A
  4. 0.3 A

Answer: A) 0.2 A

Explanation: Current splits equally. SLO P-09-E-18 · Knowledge

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