MCQs / Computer Science / Storage Units and Memory
Storage Units and Memory MCQs — Computer Science (page 2) 51 multiple-choice questions on Storage Units and Memory from Computer Science, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.
26. How many megabytes are there in 3 GB? 300 30,720 3072 3000 Answer: C) 3072
Explanation: 3 × 1024 = 3072 MB.
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27. Which statement about RAM and ROM is correct? RAM is read-write and volatile; ROM is read-only and non-volatile RAM is read-only; ROM is read-write Both are volatile Both are secondary storage Answer: A) RAM is read-write and volatile; ROM is read-only and non-volatile
Explanation: This is the key difference.
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28. Which RAM must be refreshed thousands of times per second? ROM EPROM DRAM SRAM Answer: C) DRAM
Explanation: DRAM capacitors leak charge and need refreshing.
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29. Which is an advantage of flash storage? Unlimited write cycles Needs a laser Volatile memory No moving parts, so it is durable and fast Answer: D) No moving parts, so it is durable and fast
Explanation: Flash is solid-state.
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30. RAM is: read only volatile non-volatile a secondary storage device Answer: B) volatile
Explanation: RAM loses its contents when power is switched off.
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31. A USB flash drive stores data in: flash memory vacuum tubes optical pits magnetic platters Answer: A) flash memory
Explanation: It is a solid-state device.
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32. EEPROM is erased: by breaking the chip electrically with ultraviolet light it cannot be erased Answer: B) electrically
Explanation: EEPROM = Electrically Erasable PROM.
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33. NAS stands for: National Archive Storage Network Area Server New Access System Network Attached Storage Answer: D) Network Attached Storage
Explanation: A storage device attached to a network for shared use.
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34. A nibble is equal to: 1024 bytes 8 bits 2 bytes 4 bits Answer: D) 4 bits
Explanation: Half a byte.
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35. CD-R discs can be written: only by the factory never once unlimited times Answer: C) once
Explanation: R = recordable once (WORM).
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36. A plastic card with an embedded microchip is a: magnetic tape smart card floppy disk CD-R Answer: B) smart card
Explanation: ATM chip cards and SIM cards are smart cards.
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37. ROM is: volatile non-volatile a type of hard disk erased on every shutdown Answer: B) non-volatile
Explanation: ROM keeps its contents without power.
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38. 1 GB is equal to: 1024 TB 1024 KB 1024 MB 1000 KB Answer: C) 1024 MB
Explanation: 1 GB = 1024 MB.
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39. Concentric circles on a disk surface are called: clusters pits tracks sectors Answer: C) tracks
Explanation: Tracks are circular paths.
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40. Cache memory is usually made of: magnetic tape SRAM DRAM EPROM Answer: B) SRAM
Explanation: SRAM is fast and needs no refresh.
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41. One character such as "A" usually needs: 4 bytes in all cases 1 byte 1 KB 1 bit Answer: B) 1 byte
Explanation: In ASCII, one character uses one byte.
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42. RAID 0 uses: tape backup parity on one disk striping without redundancy mirroring Answer: C) striping without redundancy
Explanation: RAID 0 splits data across disks for speed.
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43. The BIOS that starts the computer is stored in: ROM cache RAM registers Answer: A) ROM
Explanation: Firmware/BIOS is stored in ROM (flash).
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44. A standard CD can store about: 4.7 GB 700 MB 1 TB 25 GB Answer: B) 700 MB
Explanation: CDs hold about 650–700 MB.
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45. PROM can be programmed: only once only by the CPU unlimited times with ultraviolet light Answer: A) only once
Explanation: Programmable ROM is written once.
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46. RAID 1 uses: no disks striping only mirroring optical discs Answer: C) mirroring
Explanation: Data is copied identically on two disks.
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47. A hard disk stores data: on paper in vacuum tubes optically magnetically Answer: D) magnetically
Explanation: Platters are coated with magnetic material.
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48. Optical discs are read using a: magnet electron gun laser needle Answer: C) laser
Explanation: Laser light reflects from pits and lands.
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49. The time taken to move the read/write head to the correct track is: rotational delay seek time transfer time boot time Answer: B) seek time
Explanation: Seek time is the head-movement time.
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50. When the CPU finds the required data in cache, it is called a: seek cache hit page fault cache miss Answer: B) cache hit
Explanation: A hit avoids accessing slower RAM.
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