76. Joining both inputs of a NAND gate together makes a:
- OR gate
- NOT gate
- buffer
- AND gate
Answer: B) NOT gate
Explanation: (A·A)' = A', so a NAND with both inputs tied is an inverter. SLO CS-11-A-01
MCQs / Computer Science / Unit 1: Computer Systems
100 multiple-choice questions on Unit 1: Computer Systems from Computer Science, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.
Answer: B) NOT gate
Explanation: (A·A)' = A', so a NAND with both inputs tied is an inverter. SLO CS-11-A-01
Answer: C) Digital
Explanation: Digital signals use discrete levels (0 and 1); analog signals are continuous. SLO CS-11-A-01
Answer: A) A
Explanation: F = A(B + B') = A · 1 = A. SLO CS-11-A-01
Answer: C) (AB)'
Explanation: NAND is NOT-AND: (AB)'. By De Morgan it also equals A' + B'. SLO CS-11-A-01
Answer: B) NAND and NOR
Explanation: Any logic function can be built using only NAND gates or only NOR gates. SLO CS-11-A-01
Answer: C) 8
Explanation: With n inputs there are 2^n combinations: 2^3 = 8 rows. SLO CS-11-A-01
Answer: C) cross-site scripting (XSS)
Explanation: XSS injects scripts through unvalidated input. SLO CS-11-A-04
Answer: C) Mesh
Explanation: Mesh has redundant links, so data can take another path if one fails. SLO CS-11-A-03
Answer: C) the secret key must be shared safely
Explanation: Both sides need the same key, so key distribution is the problem. SLO CS-11-A-04
Answer: B) A · 1 = A
Explanation: Duality swaps AND with OR and 0 with 1, keeping the variables: A · 1 = A. SLO CS-11-A-01
Answer: C) ransomware
Explanation: Ransomware holds files to ransom. SLO CS-11-A-04
Answer: B) Requirement analysis
Explanation: Requirements gathered from users are documented in the SRS during analysis. SLO CS-11-A-02
Answer: B) A + 1 = 1
Explanation: Null law: anything OR 1 is 1. A + A' = 1, A·A' = 0 and A·1 = A. SLO CS-11-A-01
Answer: D) Asymmetric
Explanation: Asymmetric (public-key) encryption uses a key pair. SLO CS-11-A-04
Answer: C) two-factor authentication
Explanation: Two different factors – something you know and something you have. SLO CS-11-A-04
Answer: B) expensive, because earlier phases must be redone
Explanation: Waterfall phases are sequential, so going back is costly. SLO CS-11-A-02
Answer: B) Adaptive
Explanation: Adaptive maintenance adapts software to a changed environment. SLO CS-11-A-02
Answer: B) It is one-way and gives a fixed-length output
Explanation: A hash cannot be reversed and always has the same length (e.g. SHA-256 = 256 bits). SLO CS-11-A-04
Answer: D) elasticity (auto-scaling)
Explanation: Auto-scaling (elasticity) is how cloud computing provides scalability. SLO CS-11-A-03
Answer: C) 5 minutes
Explanation: 0.001% of 525 600 minutes ≈ 5.26 minutes. SLO CS-11-A-03
Answer: C) Z
Explanation: XZ(Y + Y') + X'Z = XZ + X'Z = Z(X + X') = Z. SLO CS-11-A-01
Answer: A) 1
Explanation: Each doubling of a group removes one variable: 3 − 2 = 1 variable remains. SLO CS-11-A-01
Answer: B) Waterfall
Explanation: Waterfall works best when requirements are stable and the phases are sequential. SLO CS-11-A-02
Answer: B) parallel
Explanation: Parallel running is safest for critical data but most expensive. SLO CS-11-A-02
Answer: A) Black-box testing
Explanation: Black-box testing checks inputs and outputs against the specification only. SLO CS-11-A-02
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Practise Unit 1: Computer Systems MCQs