MCQs / Physics / Current Electricity
Current Electricity MCQs — Physics (page 10) 270 multiple-choice questions on Current Electricity from Physics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.
226. A galvanometer can be converted into a voltmeter by: connecting a small shunt in parallel removing its magnet connecting a capacitor connecting a large resistance in series Answer: D) connecting a large resistance in series
Explanation: Multiplier. SLO P-09-E-24 · Understanding
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227. An LDR in a circuit is most like: a cell a variable resistor controlled by light a switch controlled by heat a fixed resistor Answer: B) a variable resistor controlled by light
Explanation: Light-controlled resistance. SLO P-09-E-14 · Knowledge
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228. If the galvanometer deflects to the left at one end of the wire and to the right at the other, then: there is no balance point the cell is flat a balance point exists between them the galvanometer is broken Answer: C) a balance point exists between them
Explanation: The deflection changes sign. SLO P-09-E-24 · Understanding
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229. The resistance of a light-dependent resistor (LDR): depends only on temperature increases as light intensity increases decreases as light intensity increases is constant Answer: C) decreases as light intensity increases
Explanation: More light, more free charge carriers. SLO P-09-E-14 · Knowledge
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230. A battery of e.m.f. 6 V has a terminal p.d. of 5 V when delivering 2 A. Its internal resistance is: 2.5 Ω 0.25 Ω 1 Ω 0.5 Ω Answer: D) 0.5 Ω
Explanation: mathcalE = V + Ir Rightarrow r = 6 - 52 = 0.5 Ω. SLO P-09-E-17 · Understanding
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231. The unit of power, the watt, equals: 1 C/s 1 V/A 1 J/s 1 J s Answer: C) 1 J/s
Explanation: Energy per second. SLO P-09-E-12 · Application
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232. A charge of 3 C moves through a p.d. of 12 V. The energy transferred is: 18 J 36 J 4 J 72 J Answer: B) 36 J
Explanation: W = QV = 36 J. SLO P-09-E-11 · Application
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233. As the current drawn from a battery increases, its terminal p.d.: decreases becomes equal to the e.m.f. increases stays constant Answer: A) decreases
Explanation: More lost volts. SLO P-09-E-17 · Understanding
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234. A source of e.m.f. 6 V and internal resistance 0.5 Ω drives a 2.5 Ω load. The power delivered to the load is: 5 W 10 W 100 W 20 W Answer: B) 10 W
Explanation: I = 63 = 2 A; P = I^2R = 10 W. SLO P-09-E-26 · Understanding
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235. A device draws 5 A from a 9 V supply. Its power is: 90 W 45 W 22.5 W 1.8 W Answer: B) 45 W
Explanation: P = IV = 45 W. SLO P-09-E-12 · Application
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236. A potential divider has 10 kΩ and 5 kΩ resistors in series across 9 V. The p.d. across the 5 kΩ resistor is: 30 V 6 V 3 V 1.5 V Answer: C) 3 V
Explanation: Vout = Vin R2R1 + R2 = 9 515 = 3 V. SLO P-09-E-25 · Understanding
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237. A copper wire has n = 1 10^29 m^-3, cross-section 5 10^-7 m^2 and drift velocity 2 10^-4 m/s. The current is (e = 1.6 10^-19 C): 0.16 A 16 A 1.6 A 3.2 A Answer: C) 1.6 A
Explanation: I = nAvq = 1 10^29 5 10^-7 2 10^-4 1.6 10^-19 = 1.6 A. SLO P-09-E-10 · Application
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238. An LDR's resistance might change from about 1 MΩ in the dark to: 1 MΩ unchanged infinity a few hundred ohms in bright light 10 MΩ in bright light Answer: C) a few hundred ohms in bright light
Explanation: Large range. SLO P-09-E-14 · Knowledge
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239. A galvanometer with a centre-zero scale is useful because: it measures voltage only it measures very large currents it never deflects it shows current in either direction Answer: D) it shows current in either direction
Explanation: Helps find balance. SLO P-09-E-24 · Understanding
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240. Old-style fairy lights in series all go out when one bulb fails because: the other bulbs blow the voltage rises the current increases the circuit is broken, so no current flows Answer: D) the circuit is broken, so no current flows
Explanation: Single path. SLO P-09-E-20 · Application
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241. Resistors of 100 Ω, 220 Ω, 330 Ω are connected in series. The combined resistance is: 1300 Ω 650 Ω 6500 Ω 325 Ω Answer: B) 650 Ω
Explanation: R = R1 + R2 + ldots = 650 Ω. SLO P-09-E-20 · Application
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242. In a potential divider with two equal resistors across 10 V, the output across one is: 10 V 2.5 V 20 V 5 V Answer: D) 5 V
Explanation: Equal share. SLO P-09-E-25 · Understanding
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243. Semiconductors have a much smaller n than metals, so for the same current and area their drift velocity is: much larger zero much smaller the same Answer: A) much larger
Explanation: v propto 1/n. SLO P-09-E-10 · Application
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244. A galvanometer can be converted into an ammeter by: adding a battery removing its coil connecting a large resistance in series connecting a small resistance (shunt) in parallel Answer: D) connecting a small resistance (shunt) in parallel
Explanation: Not a null method, but its other use. SLO P-09-E-24 · Understanding
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245. The circuit symbol for an LDR is: a resistor with arrows pointing towards it a diode a resistor with arrows pointing away a circle with a cross Answer: A) a resistor with arrows pointing towards it
Explanation: Arrows show incoming light. SLO P-09-E-14 · Knowledge
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246. In a series circuit, the p.d. across each resistor is: inversely proportional to its resistance zero the same for all resistors proportional to its resistance Answer: D) proportional to its resistance
Explanation: V = IR with the same I. SLO P-09-E-20 · Application
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247. In a complete circuit, the sum of the p.d.s around the loop equals: the current zero always the resistance the sum of the e.m.f.s Answer: D) the sum of the e.m.f.s
Explanation: Energy conservation (Kirchhoff's second law). SLO P-09-E-16 · Understanding
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248. A wire has resistivity 4.9 10^-7 Ω m, length 2 m and cross-section 5 10^-7 m^2. Its resistance is: 3.92 Ω 19.6 Ω 1.96 Ω 0.196 Ω Answer: C) 1.96 Ω
Explanation: R = rho LA = 1.96 Ω. SLO P-09-E-13 · Application
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249. Inspectors can easily check the bridge because the method needs only: heavy cranes divers dismantling the bridge simple electrical measurements at connection points Answer: D) simple electrical measurements at connection points
Explanation: Easy and quick. SLO P-09-E-27 · Understanding
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250. Resistors of 10 Ω, 40 Ω are connected in parallel. The combined resistance is: 16 Ω 4 Ω 80 Ω 8 Ω Answer: D) 8 Ω
Explanation: 1R = 110 + 140 Rightarrow R = 8 Ω. SLO P-09-E-21 · Application
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