MCQs / Physics / Current Electricity
Current Electricity MCQs — Physics (page 9) 270 multiple-choice questions on Current Electricity from Physics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.
201. When a loaded bridge deck bends, the strained carbon fibres show: a change in mass a change in colour no change a change in resistance Answer: D) a change in resistance
Explanation: Strain-sensing. SLO P-09-E-27 · Understanding
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202. If the same charge moves through twice the p.d., the energy transferred: is unchanged quadruples doubles halves Answer: C) doubles
Explanation: W = QV. SLO P-09-E-11 · Application
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203. In a balanced Wheatstone bridge with P = 10 Ω, Q = 20 Ω, R = 15 Ω, the unknown S is: 13.3 Ω 7.5 Ω 30 Ω 45 Ω Answer: C) 30 Ω
Explanation: PQ = RS. SLO P-09-E-22 · Application
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204. The physics principle behind the carbon-fibre method is: the Doppler effect Snell's law resistance depends on length and cross-section of the conducting path (R = rho L/A) Archimedes' principle Answer: C) resistance depends on length and cross-section of the conducting path (R = rho L/A)
Explanation: Damage changes the effective L and A. SLO P-09-E-27 · Understanding
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205. In a null method, the galvanometer is used to show: the resistance the exact value of a large current when the current through it is zero the e.m.f. directly Answer: C) when the current through it is zero
Explanation: Balance condition. SLO P-09-E-24 · Understanding
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206. Resistivity depends on: the area of the wire the material and temperature the length of the wire the current Answer: B) the material and temperature
Explanation: A property of the material. SLO P-09-E-13 · Application
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207. 24 J of energy is transferred when 2 C of charge passes between two points. The p.d. is: 12 V 24 V 48 V 6 V Answer: A) 12 V
Explanation: V = WQ = 242 = 12 V. SLO P-09-E-11 · Application
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208. The e.m.f. of a source is equal to the terminal p.d. when: a large current is drawn no current is drawn the circuit is short-circuited the cell is flat Answer: B) no current is drawn
Explanation: No internal loss. SLO P-09-E-16 · Understanding
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209. A graph of terminal p.d. V against current I for a cell has a gradient of: -r 1r mathcalE r Answer: A) -r
Explanation: V = mathcalE - rI; intercept = e.m.f. SLO P-09-E-17 · Understanding
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210. n identical resistors R in parallel have a combined resistance of: nR nR Rn R Answer: C) Rn
Explanation: Each adds 1/R. SLO P-09-E-21 · Application
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211. An electron (charge 1.6 10^-19 C) moves through a p.d. of 5 V. The energy transferred is: 8.0 10^-19 J 3.1 10^19 J 5 J 3.2 10^-20 J Answer: A) 8.0 10^-19 J
Explanation: W = QV = 1.6 10^-19 5 = 5 eV. SLO P-09-E-11 · Application
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212. Replacing the fixed resistor in a sensing potential divider with a variable resistor allows: the supply voltage to change the sensor to work in reverse the switching point (sensitivity) to be adjusted zero output always Answer: C) the switching point (sensitivity) to be adjusted
Explanation: Set the threshold. SLO P-09-E-25 · Understanding
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213. A cell transfers 3 J of energy to 2 C of charge driven round a complete circuit. Its e.m.f. is: 0.75 V 3 V 6 V 1.5 V Answer: D) 1.5 V
Explanation: mathcalE = WQ = 1.5 V. SLO P-09-E-15 · Application
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214. Thermistors are used in potential dividers to: provide a p.d. that depends on temperature store energy measure current provide a constant p.d. Answer: A) provide a p.d. that depends on temperature
Explanation: Temperature sensors. SLO P-09-E-25 · Understanding
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215. Kirchhoff's second law is also called: Faraday's law the junction rule the loop rule Coulomb's law Answer: C) the loop rule
Explanation: KVL. SLO P-09-E-19 · Understanding
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216. The short-circuit current of a 1.5 V cell with internal resistance 0.5 Ω is: 0.33 A 3 A 0.75 A 1.5 A Answer: B) 3 A
Explanation: I = mathcalE/r. SLO P-09-E-17 · Understanding
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217. Resistors of 2 Ω, 3 Ω, 5 Ω are connected in series. The combined resistance is: 5 Ω 100 Ω 20 Ω 10 Ω Answer: D) 10 Ω
Explanation: R = R1 + R2 + ldots = 10 Ω. SLO P-09-E-20 · Application
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218. Starting from V = V1 + V2 with V = IR, V1 = IR1, V2 = IR2, we get: R = R1R2 1R = 1R1 + 1R2 R = R1 - R2 R = R1 + R2 Answer: D) R = R1 + R2
Explanation: Divide by I. SLO P-09-E-20 · Application
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219. Resistors of 1 Ω, 2 Ω, 6 Ω are in series with a 9 V supply. The current is: 2 A 9 A 1 A 0.5 A Answer: C) 1 A
Explanation: R = 9 Ω; I = VR = 1 A. SLO P-09-E-20 · Application
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220. The unit of e.m.f. is: newton ampere volt ohm Answer: C) volt
Explanation: J/C. SLO P-09-E-15 · Application
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221. An ammeter in the main line reads 5 A; ammeters in two of three parallel branches read 1.5 A and 2 A. The third branch reads: 1.5 A 0.5 A 3.5 A 8.5 A Answer: A) 1.5 A
Explanation: 5 - 1.5 - 2. SLO P-09-E-18 · Knowledge
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222. When a cell is balanced on a potentiometer, the e.m.f. measured is not affected by its internal resistance because: the galvanometer cancels it the wire has no resistance the driver cell supplies extra p.d. no current flows through the cell Answer: D) no current flows through the cell
Explanation: No lost volts at balance. SLO P-09-E-23 · Application
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223. Kirchhoff's first law applies to: every junction in any circuit only AC circuits only series circuits only batteries Answer: A) every junction in any circuit
Explanation: General law. SLO P-09-E-18 · Knowledge
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224. Two 10 Ω resistors in parallel are then put in series with a 5 Ω resistor. The total resistance is: 5 Ω 15 Ω 25 Ω 10 Ω Answer: D) 10 Ω
Explanation: 5 + 5 = 10 Ω. SLO P-09-E-21 · Application
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225. If cracks form in carbon-fibre-reinforced concrete, the electrical resistance of the fibres: becomes zero decreases stays the same increases Answer: D) increases
Explanation: Broken or stretched conducting paths. SLO P-09-E-27 · Understanding
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