MCQs / Physics / Electrostatics
Electrostatics MCQs — Physics (page 4) 120 multiple-choice questions on Electrostatics from Physics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.
76. Mobile phones often lose signal inside lifts because: the metal lift acts as a Faraday cage lifts have no air the phone's battery drains lifts are too high Answer: A) the metal lift acts as a Faraday cage
Explanation: Radio waves are blocked. SLO P-11-E-06 · Understanding
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77. N/C is equivalent to: W/A C/m J/C V/m Answer: D) V/m
Explanation: 1 N/C = 1 V/m. SLO P-11-E-02 · Application
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78. The electric field inside a charged hollow conducting sphere is: directed outward the same as at the surface infinite zero Answer: D) zero
Explanation: No field inside a conductor. SLO P-11-E-05 · Knowledge
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79. If the distance from a point charge is tripled, the field strength becomes: nine times one third three times one ninth Answer: D) one ninth
Explanation: E propto 1/r^2. SLO P-11-E-08 · Application
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80. An electric field is a region in which: a charge experiences a force no force acts a magnet always experiences a force a mass experiences a force Answer: A) a charge experiences a force
Explanation: Field of force acting on charges. SLO P-11-E-01 · Knowledge
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81. For a mesh to act as a Faraday cage for waves, the holes must be: equal to the wavelength much smaller than the wavelength any size much larger than the wavelength Answer: B) much smaller than the wavelength
Explanation: Otherwise the waves pass through. SLO P-11-E-06 · Understanding
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82. An electron is between parallel plates 1 cm apart with 500 V across them. Its acceleration is (e = 1.6 10^-19 C, me = 9.11 10^-31 kg): 8.78 10^14 m/s^2 4.78 10^12 m/s^2 8.78 10^16 m/s^2 8.78 10^15 m/s^2 Answer: D) 8.78 10^15 m/s^2
Explanation: E = 50,000 V/m; a = eEm = 8.78 10^15 m/s^2. SLO P-11-E-04 · Understanding
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83. In Coulomb's law, k = 1varepsilon0 varepsilon04pi 14pivarepsilon0 4pivarepsilon0 Answer: C) 14pivarepsilon0
Explanation: varepsilon0 is the permittivity of free space. SLO P-11-E-07 · Application
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84. The number of field lines leaving a charge is proportional to: the size of the charge the distance from it the mass of the charge its speed Answer: A) the size of the charge
Explanation: Bigger charge, more lines. SLO P-11-E-03 · Understanding
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85. The field lines between two charged parallel plates are: radial circular parallel and equally spaced curved and crossing Answer: C) parallel and equally spaced
Explanation: Uniform field. SLO P-11-E-03 · Understanding
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86. Sensitive electronic equipment is placed in metal boxes to: keep it warm increase its current shield it from external electric fields and interference make it heavier Answer: C) shield it from external electric fields and interference
Explanation: Electrostatic shielding. SLO P-11-E-06 · Understanding
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87. A charged balloon attracts small bits of paper because: of magnetism of gravity of air pressure its electric field exerts forces on charges in the paper Answer: D) its electric field exerts forces on charges in the paper
Explanation: Induced charges are attracted. SLO P-11-E-01 · Knowledge
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88. The metal mesh in a microwave oven door: heats the food keeps microwaves inside while letting visible light through reflects light lets microwaves out Answer: B) keeps microwaves inside while letting visible light through
Explanation: Holes are smaller than the microwave wavelength. SLO P-11-E-06 · Understanding
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89. A charge of 1.6 10^-19 C experiences a force of 6 10^-15 N. The electric field strength is: 3750 N/C 75,000 N/C 3.75 10^5 N/C 37,500 N/C Answer: D) 37,500 N/C
Explanation: E = Fq = 37,500 N/C. SLO P-11-E-02 · Application
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90. Two parallel plates 2 cm apart have a p.d. of 200 V between them. The field strength between them is: 100 V/m 1000 V/m 10,000 V/m 1 10^5 V/m Answer: C) 10,000 V/m
Explanation: E = Delta VDelta d = 2000.02 = 10,000 V/m. SLO P-11-E-02 · Application
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91. Distances for the field outside a charged sphere are measured from: the surface of the sphere the centre of the sphere the nearest edge infinity Answer: B) the centre of the sphere
Explanation: Point charge at the centre. SLO P-11-E-05 · Knowledge
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92. A metal sphere of radius 0.1 m carries 5 10^-9 C. The field strength 0.2 m from its centre is (k = 8.99 10^9 N m^2 C^-2): 1120 N/C 562 N/C 2250 N/C 4490 N/C Answer: A) 1120 N/C
Explanation: Treat the charge as a point at the centre: E = kQr^2 = 1120 N/C (measure r from the centre). SLO P-11-E-05 · Knowledge
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93. The electric field strength 0.1 m from a point charge of 1 10^-9 C in free space is: 449 N/C 899 N/C 89.9 N/C 1800 N/C Answer: B) 899 N/C
Explanation: E = kQr^2 = 8.99 10^9 1 10^-9(0.1)^2 = 899 N/C. SLO P-11-E-08 · Application
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94. The deflection of a charged particle passing between plates increases if: the p.d. between the plates is increased the plates are made shorter the plates are moved further apart the particle moves faster Answer: A) the p.d. between the plates is increased
Explanation: Stronger field, more force. SLO P-11-E-04 · Understanding
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95. The point-charge approximation for a sphere is valid: only inside the sphere everywhere including inside never only for points outside (or on) the sphere Answer: D) only for points outside (or on) the sphere
Explanation: Inside a conductor the field is zero. SLO P-11-E-05 · Knowledge
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96. The value of varepsilon0 is about: 8.85 10^-12 F/m 6.67 10^-11 F/m 8.99 10^9 F/m 1.6 10^-19 F/m Answer: A) 8.85 10^-12 F/m
Explanation: Permittivity of free space. SLO P-11-E-07 · Application
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97. A difference between electric and gravitational fields is that electric forces: act only on masses are much weaker can be attractive or repulsive are always attractive Answer: C) can be attractive or repulsive
Explanation: Gravity only attracts. SLO P-11-E-01 · Knowledge
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98. The field 0.5 m from a point charge is 3.6 10^5 N/C. The charge is: 1 10^-5 C 5.01 10^-6 C 1 10^-4 C 2 10^-5 C Answer: A) 1 10^-5 C
Explanation: Q = Er^2k = 1 10^-5 C. SLO P-11-E-08 · Application
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99. An electric field is an example of a: temperature field sound field scalar field only field of force Answer: D) field of force
Explanation: Like gravitational and magnetic fields. SLO P-11-E-01 · Knowledge
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100. Coulomb's law states that the force between two point charges is: proportional to the separation proportional to the sum of the charges independent of distance proportional to the product of the charges and inversely proportional to the square of their separation Answer: D) proportional to the product of the charges and inversely proportional to the square of their separation
Explanation: F = kQ1Q2r^2. SLO P-11-E-07 · Application
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