MCQs / Physics / Electrostatics
Electrostatics MCQs — Physics (page 5) 120 multiple-choice questions on Electrostatics from Physics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.
101. Unlike charges: exert no force attract each other become neutral repel each other Answer: B) attract each other
Explanation: Basic law of charges. SLO P-11-E-07 · Application
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102. A Faraday cage does NOT protect against: static magnetic fields (e.g. from a bar magnet) external static electric fields lightning strikes radio interference Answer: A) static magnetic fields (e.g. from a bar magnet)
Explanation: A conducting cage doesn't screen steady magnetic fields. SLO P-11-E-06 · Understanding
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103. A charged sphere's field lines outside it are: circular radial, like those of a point charge absent parallel Answer: B) radial, like those of a point charge
Explanation: Spherical symmetry. SLO P-11-E-05 · Knowledge
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104. The electric field around an isolated positive charge points: towards the nearest negative charge only radially inward radially outward in circles Answer: C) radially outward
Explanation: Away from positive charges. SLO P-11-E-01 · Knowledge
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105. A neutral point in an electric field is where: charges are created the field is maximum the resultant field is zero field lines start Answer: C) the resultant field is zero
Explanation: Fields cancel. SLO P-11-E-03 · Understanding
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106. The field strength of a point charge and Coulomb's law are linked because: E = kQqr E = Fq E = kQr^2 E = Fq = kQq/r^2q = kQr^2 Answer: D) E = Fq = kQq/r^2q = kQr^2
Explanation: Divide the Coulomb force by the test charge. SLO P-11-E-08 · Application
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107. A charge of 3 10^-6 C is placed in an electric field of 400 N/C. The force on it is: 0.0024 N 0.012 N 0.0012 N 1.2 10^-4 N Answer: C) 0.0012 N
Explanation: F = qE = 3 10^-6 400 = 0.0012 N. SLO P-11-E-02 · Application
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108. Halving the separation of parallel plates (same p.d.) makes the field strength: half unchanged double four times Answer: C) double
Explanation: E propto 1/d. SLO P-11-E-02 · Application
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109. The field lines around an isolated point charge are: parallel lines concentric circles radial straight lines spirals Answer: C) radial straight lines
Explanation: Spread equally in all directions. SLO P-11-E-03 · Understanding
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110. The electric field strength 5.3 10^-11 m from a point charge of 1.6 10^-19 C in free space is: 2.56 10^11 N/C 1.02 10^12 N/C 5.12 10^11 N/C 27.1 N/C Answer: C) 5.12 10^11 N/C
Explanation: E = kQr^2 = 8.99 10^9 1.6 10^-19(5.3 10^-11)^2 = 5.12 10^11 N/C. SLO P-11-E-08 · Application
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111. The electric field strength 0.3 m from a point charge of 2 10^-6 C in free space is: 2 10^5 N/C 99,900 N/C 59,900 N/C 4 10^5 N/C Answer: A) 2 10^5 N/C
Explanation: E = kQr^2 = 8.99 10^9 2 10^-6(0.3)^2 = 2 10^5 N/C. SLO P-11-E-08 · Application
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112. Charges of 1.6 10^-19 C and 1.6 10^-19 C are 1 10^-10 m apart in free space. The force between them is (k = 8.99 10^9 N m^2 C^-2): 2.3 10^-18 N, repulsive 2.3 10^-8 N, attractive 4.6 10^-8 N, repulsive 2.3 10^-8 N, repulsive Answer: D) 2.3 10^-8 N, repulsive
Explanation: F = kq1q2r^2 = 2.3 10^-8 N; like charges repel. SLO P-11-E-07 · Application
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113. Field lines from a positive and a negative charge (a dipole): form closed loops round each charge never connect go from the positive charge to the negative charge go from negative to positive Answer: C) go from the positive charge to the negative charge
Explanation: Curved lines joining them. SLO P-11-E-03 · Understanding
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114. Electric field lines show: the path of light the force on a neutron the direction of a current the direction of the force on a positive charge Answer: D) the direction of the force on a positive charge
Explanation: Lines of force. SLO P-11-E-03 · Understanding
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115. The force between two charges in a medium other than vacuum is: smaller than in a vacuum zero the same larger than in a vacuum Answer: A) smaller than in a vacuum
Explanation: Divided by the relative permittivity. SLO P-11-E-07 · Application
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116. Charges of 1 10^-6 C and 1 10^-6 C are 1 m apart in free space. The force between them is (k = 8.99 10^9 N m^2 C^-2): 0.00899 N, repulsive 0.018 N, repulsive 0.00900 N, repulsive 0.00899 N, attractive Answer: A) 0.00899 N, repulsive
Explanation: F = kq1q2r^2 = 0.00899 N; like charges repel. SLO P-11-E-07 · Application
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117. Between two parallel plates, the electric field is: uniform (same everywhere except near the edges) radial zero strongest at the centre only Answer: A) uniform (same everywhere except near the edges)
Explanation: Parallel, equally spaced field lines. SLO P-11-E-02 · Application
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118. Charges of 5 10^-9 C and -4 10^-9 C are 0.02 m apart in free space. The force between them is (k = 8.99 10^9 N m^2 C^-2): 8.99 10^-6 N, attractive 4.49 10^-4 N, repulsive 8.99 10^-4 N, attractive 4.49 10^-4 N, attractive Answer: D) 4.49 10^-4 N, attractive
Explanation: F = kq1q2r^2 = 4.49 10^-4 N; unlike charges attract. SLO P-11-E-07 · Application
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119. Charges of 4 10^-6 C and -2 10^-6 C are 0.3 m apart in free space. The force between them is (k = 8.99 10^9 N m^2 C^-2): 1.6 N, attractive 0.24 N, attractive 0.799 N, attractive 0.799 N, repulsive Answer: C) 0.799 N, attractive
Explanation: F = kq1q2r^2 = 0.799 N; unlike charges attract. SLO P-11-E-07 · Application
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120. If the distance between two charges is doubled, the force becomes: one quarter double half four times Answer: A) one quarter
Explanation: Inverse square. SLO P-11-E-07 · Application
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