MCQs / Physics / Kinetic Theory and First Law of Thermodynamics
Kinetic Theory and First Law of Thermodynamics MCQs — Physics (page 7) 180 multiple-choice questions on Kinetic Theory and First Law of Thermodynamics from Physics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.
151. A cup of hot tea left in a room eventually: reaches the room's temperature becomes hotter becomes colder than the room stays hot forever Answer: A) reaches the room's temperature
Explanation: It comes to thermal equilibrium. SLO P-12-C-01 · Knowledge
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152. A body at 80 °C is placed in contact with a body at 20 °C (isolated system). Their final common temperature is: 80 °C 20 °C between 20 °C and 80 °C 100 °C Answer: C) between 20 °C and 80 °C
Explanation: The hot one cools and the cold one warms. SLO P-12-C-01 · Knowledge
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153. A gas receives 600 J of heat and its internal energy rises by 600 J. The work done by the gas is: 0 J -600 J 1200 J 600 J Answer: A) 0 J
Explanation: W = Q - Delta U = 0 (constant volume). SLO P-11-C-11 · Application
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154. The SI unit of thermodynamic temperature is: kelvin calorie joule degree Celsius Answer: A) kelvin
Explanation: A base SI unit. SLO P-12-C-01 · Knowledge
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155. In the sign convention Delta U = Q + Won, a gas that is compressed has: Won = 0 Won 0 Won < 0 Q = 0 always Answer: B) Won 0
Explanation: Work done on the gas is positive in compression. SLO P-11-C-07 · Understanding
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156. 1 J of work equals: 1 Pa m 1 Pa m^3 1 Pa/m^3 1 N/m Answer: B) 1 Pa m^3
Explanation: N m^-2 × m^3 = N m. SLO P-11-C-06 · Application
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157. 3 mol of an ideal gas at 350 K occupies 0.1 m^3. Its pressure is (R = 8.31 J mol^-1 K^-1): 8730 Pa 8.73 10^5 Pa 1.75 10^5 Pa 87,300 Pa Answer: D) 87,300 Pa
Explanation: P = nRTV = 3 8.31 3500.1 = 87,300 Pa. SLO P-11-C-03 · Application
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158. Isothermal curves on a p–V diagram at higher temperatures lie: on the axes further from the origin on the same curve closer to the origin Answer: B) further from the origin
Explanation: pV = nRT is larger. SLO P-11-C-10 · Application
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159. The internal energy of 1 mol of a monatomic ideal gas is U = 32nRT. When it is heated from 300 K to 400 K, its internal energy increases by: 1250 J 2490 J 831 J 623 J Answer: A) 1250 J
Explanation: Delta U = 32nRDelta T = 1.5 1 8.31 100 = 1250 J. SLO P-11-C-12 · Understanding
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160. The area under an isothermal p–V curve between two volumes represents: the work done by the gas the temperature the heat capacity the pressure Answer: A) the work done by the gas
Explanation: As for any p–V graph. SLO P-11-C-10 · Application
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161. When an ideal gas expands isothermally, the heat absorbed: is wasted is all converted into work done by the gas decreases internal energy increases internal energy Answer: B) is all converted into work done by the gas
Explanation: Delta U = 0 Rightarrow Q = W. SLO P-11-C-11 · Application
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162. For an adiabatic change: Q = 0, Delta U = -W Q = W Delta U = 0 W = 0 Answer: A) Q = 0, Delta U = -W
Explanation: No heat exchanged. SLO P-11-C-08 · Application
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163. Thermal equilibrium is reached faster when: they are in a vacuum flask the bodies are good thermal conductors and in good contact they are insulated from each other they have no contact Answer: B) the bodies are good thermal conductors and in good contact
Explanation: Energy transfer is faster. SLO P-12-C-01 · Knowledge
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164. In the compression stroke of an engine, the piston: receives work from the gas does work on the gas cools the gas does no work Answer: B) does work on the gas
Explanation: Compression. SLO P-11-C-07 · Understanding
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165. For an isothermal change of an ideal gas: Q = 0 W = 0 Delta U = 0, Q = W Delta U = Q Answer: C) Delta U = 0, Q = W
Explanation: Constant T ⇒ constant internal energy. SLO P-11-C-08 · Application
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166. The Boltzmann constant links: mass with energy the energy of a molecule with absolute temperature charge with current frequency with energy Answer: B) the energy of a molecule with absolute temperature
Explanation: e.g. barEk = 32kT. SLO P-11-C-04 · Knowledge
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167. Why does a gas fill any container it is put in? it is attracted by the walls it has a fixed volume its molecules move randomly and freely in all directions it is heavier than air Answer: C) its molecules move randomly and freely in all directions
Explanation: No strong intermolecular forces. SLO P-11-C-09 · Understanding
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168. Which quantity decides the direction of heat flow? temperature heat capacity mass internal energy Answer: A) temperature
Explanation: A large cold lake can have more internal energy than a hot nail. SLO P-12-C-01 · Knowledge
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169. A bubble rising from the bottom of a lake (constant temperature) grows bigger because: the water pushes it outward the water pressure on it decreases the temperature rises gas is added Answer: B) the water pressure on it decreases
Explanation: Boyle's law. SLO P-11-C-09 · Understanding
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170. The number of molecules in 2 mol of gas is: 2.76 10^-23 3.01 10^23 6.02 10^23 1.20 10^24 Answer: D) 1.20 10^24
Explanation: N = nNA = 2 6.02 10^23. SLO P-11-C-04 · Knowledge
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171. If the internal energy of a fixed mass of ideal gas increases, its temperature must: become zero stay the same decrease increase Answer: D) increase
Explanation: U propto T for an ideal gas. SLO P-11-C-12 · Understanding
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172. The Boltzmann constant is related to the molar gas constant by: k = NAR k = R + NA k = RNA k = RNA Answer: D) k = RNA
Explanation: The gas constant per molecule. SLO P-11-C-04 · Knowledge
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173. 2 mol of an ideal gas at 300 K occupies 0.05 m^3. Its pressure is (R = 8.31 J mol^-1 K^-1): 99,700 Pa 9970 Pa 1.99 10^5 Pa 9.97 10^5 Pa Answer: A) 99,700 Pa
Explanation: P = nRTV = 2 8.31 3000.05 = 99,700 Pa. SLO P-11-C-03 · Application
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174. At high pressure a real gas departs from ideal behaviour because: the molecules stop moving the gas becomes a solid the molecules' own volume becomes significant temperature becomes zero Answer: C) the molecules' own volume becomes significant
Explanation: The point-molecule assumption fails. SLO P-11-C-05 · Understanding
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175. Doubling the number of gas molecules in a fixed container at constant temperature: quadruples the pressure doubles the pressure halves the pressure does not change pressure Answer: B) doubles the pressure
Explanation: Twice as many collisions. SLO P-11-C-09 · Understanding
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