MCQs / Physics / Magnetism and Electromagnetic Induction
Magnetism and Electromagnetic Induction MCQs — Physics (page 3) 255 multiple-choice questions on Magnetism and Electromagnetic Induction from Physics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.
51. The minus sign in mathcalE = - Delta(NPhi)Delta t represents: Faraday's law Coulomb's law Lenz's law Ohm's law Answer: C) Lenz's law
Explanation: Opposition. SLO P-09-E-41 · Understanding
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52. The particles in a ferrofluid are coated with a surfactant to: make them magnetic change their colour stop them clumping together make them heavier Answer: C) stop them clumping together
Explanation: Keeps them suspended. SLO P-09-E-09 · Understanding
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53. Doubling the flux density doubles the force on a current-carrying wire because: F propto 1B F = BILsintheta propto B the current doubles F propto B^2 Answer: B) F = BILsintheta propto B
Explanation: Direct proportion. SLO P-09-E-31 · Knowledge
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54. A ferrofluid in a strong magnetic field becomes: magnetised and is attracted to regions of strong field repelled from the magnet electrically charged transparent Answer: A) magnetised and is attracted to regions of strong field
Explanation: Pulled towards the magnet. SLO P-09-E-09 · Understanding
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55. For a charge in a magnetic field, the centripetal force is provided by: the magnetic force Bqv air resistance gravity the electric force Answer: A) the magnetic force Bqv
Explanation: Bqv = mv^2r. SLO P-09-E-33 · Understanding
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56. If the speed of the particle is doubled, the radius of its circular path: halves quadruples doubles stays the same Answer: C) doubles
Explanation: r propto v. SLO P-09-E-33 · Understanding
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57. A strong laboratory magnet produces a flux density of about: 1000 T 0.1–1 T 10^-9 T 10^-5 T Answer: B) 0.1–1 T
Explanation: MRI scanners: 1.5–3 T. SLO P-09-E-31 · Knowledge
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58. The speed of a charged particle moving in a circle in a magnetic field: oscillates decreases stays constant increases Answer: C) stays constant
Explanation: Magnetic force does no work. SLO P-09-E-33 · Understanding
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59. The definition of magnetic flux uses the area: of the wire's cross-section of the magnet's pole perpendicular to the direction of the field parallel to the field Answer: C) perpendicular to the direction of the field
Explanation: As in the SLO. SLO P-09-E-38 · Knowledge
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60. When the N pole of a magnet is withdrawn from a coil, the near end of the coil becomes: negatively charged neutral a north pole a south pole (attracting the magnet) Answer: D) a south pole (attracting the magnet)
Explanation: Opposes the withdrawal. SLO P-09-E-41 · Understanding
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61. A neutral particle entering a velocity selector: is stopped is deflected by B is deflected by E passes straight through whatever its speed Answer: D) passes straight through whatever its speed
Explanation: No forces on it. SLO P-09-E-34 · Understanding
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62. The Earth's magnetic field is roughly like that of: a single pole a bar magnet a flat coil only a straight wire Answer: B) a bar magnet
Explanation: Geomagnetic field. SLO P-09-E-28 · Knowledge
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63. A straight conductor 1.5 m long moves at 20 m/s at right angles to a 0.05 T field. The induced e.m.f. is: 0.00375 V 0.75 V 3 V 1.5 V Answer: D) 1.5 V
Explanation: mathcalE = BLv = 1.5 V. SLO P-09-E-42 · Application
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64. The flux through each of 200 turns of a coil changes by 0.03 Wb in 0.1 s. The average induced e.m.f. is: 60 V 0.3 V 30 V 120 V Answer: A) 60 V
Explanation: mathcalE = N DeltaPhiDelta t = 200 0.030.1 = 60 V. SLO P-09-E-42 · Application
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65. Holding the magnet still inside the coil gives: a steady deflection a growing deflection a reversed deflection no deflection Answer: D) no deflection
Explanation: No change of flux. SLO P-09-E-41 · Understanding
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66. To find the force direction on wire 2 due to wire 1, you use: Lenz's law only Coulomb's law Newton's law of gravitation the right-hand grip rule for the field of wire 1 and then Fleming's left-hand rule for wire 2 Answer: D) the right-hand grip rule for the field of wire 1 and then Fleming's left-hand rule for wire 2
Explanation: Two-step method. SLO P-09-E-37 · Understanding
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67. One tesla is the flux density that produces a force of: 1 J on 1 C 1 N on a charge of 1 C at rest 1 W per m^2 1 N on a 1 m wire carrying 1 A at right angles to the field Answer: D) 1 N on a 1 m wire carrying 1 A at right angles to the field
Explanation: Definition. SLO P-09-E-31 · Knowledge
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68. The two wires of a mains flex carry currents in opposite directions, so they: twist together repel slightly attract strongly exert no force Answer: B) repel slightly
Explanation: Opposite currents. SLO P-09-E-37 · Understanding
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69. Ferrofluids were first developed by NASA for: space suits rocket engines' fire controlling fuel flow in zero gravity radio communications Answer: C) controlling fuel flow in zero gravity
Explanation: Moving fuel with magnets. SLO P-09-E-09 · Understanding
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70. A straight conductor 0.2 m long moves at 4 m/s at right angles to a 0.5 T field. The induced e.m.f. is: 0.2 V 0.025 V 0.4 V 0.8 V Answer: C) 0.4 V
Explanation: mathcalE = BLv = 0.4 V. SLO P-09-E-42 · Application
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71. A circular loop of radius 5 cm is perpendicular to a 0.2 T field. The flux through it is: 0.00157 Wb 7.85 10^-4 Wb 0.00314 Wb 5 10^-4 Wb Answer: A) 0.00157 Wb
Explanation: A = pi r^2 = 0.00785 m^2; Phi = BA = 0.00157 Wb. SLO P-09-E-39 · Application
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72. When the N pole of a magnet is pushed into a coil, the near end of the coil becomes: neutral a south pole (attracting the magnet) positively charged a north pole (repelling the magnet) Answer: D) a north pole (repelling the magnet)
Explanation: Opposes the approach. SLO P-09-E-41 · Understanding
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73. A coil of area 0.1 m^2 is in a 0.8 T field; the field makes 30^circ with the normal to the coil. The flux through the coil is: 0.0346 Wb 0.693 Wb 0.139 Wb 0.0693 Wb Answer: D) 0.0693 Wb
Explanation: Phi = BAcostheta = 0.8 0.1 cos 30^circ = 0.0693 Wb. SLO P-09-E-39 · Application
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74. In a velocity selector, E = 3 10^5 V/m and B = 0.6 T are at right angles. The speed of particles that pass through undeflected is: 2.5 10^5 m/s 5 10^5 m/s 1.8 10^5 m/s 1 10^6 m/s Answer: B) 5 10^5 m/s
Explanation: qE = Bqv Rightarrow v = EB = 5 10^5 m/s. SLO P-09-E-34 · Understanding
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75. 1 T = 1 Wb m^-2 shows that flux density is: area per unit flux flux per unit area flux times area force per charge Answer: B) flux per unit area
Explanation: B = Phi/A. SLO P-09-E-31 · Knowledge
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