MCQs / Physics / Superposition, Stationary Waves and Beats
Superposition, Stationary Waves and Beats MCQs — Physics (page 2) 150 multiple-choice questions on Superposition, Stationary Waves and Beats from Physics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.
26. A guitarist plays the same note on two strings and hears 2 beats per second. This means: the strings are 2 Hz out of tune the strings are perfectly tuned one string is broken the strings are an octave apart Answer: A) the strings are 2 Hz out of tune
Explanation: fb = f1 - f2. SLO P-11-D-16 · Application
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27. For destructive interference from in-phase sources, the path difference is: lambdan (n + tfrac12)lambda 2nlambda nlambda Answer: B) (n + tfrac12)lambda
Explanation: Half-wavelength offsets. SLO P-11-D-08 · Understanding
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28. For effective cancellation, the delay in generating anti-noise must be: very small compared with the period of the noise exactly one second unimportant much longer than the period Answer: A) very small compared with the period of the noise
Explanation: Otherwise the phase will be wrong. SLO P-11-D-09 · Understanding
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29. When an orchestra tunes before a concert, the oboe plays a reference A so that other players can: play louder change the speed of sound make faster beats eliminate beats with it Answer: D) eliminate beats with it
Explanation: Tuning by beats. SLO P-11-D-16 · Application
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30. The beat frequency equals: the average of the frequencies the sum of the two frequencies the difference between the two frequencies the product of the frequencies Answer: C) the difference between the two frequencies
Explanation: fb = f1 - f2. SLO P-11-D-15 · Understanding
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31. Superposition applies to: only water waves all types of waves only sound waves only light waves Answer: B) all types of waves
Explanation: A general principle (for linear media). SLO P-11-D-07 · Application
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32. For the same string (length 0.8 m, wave speed 320 m/s), the frequency of the third harmonic is: 800 Hz 400 Hz 200 Hz 600 Hz Answer: D) 600 Hz
Explanation: f3 = 3f1 = 3 200 = 600 Hz. SLO P-11-D-12 · Understanding
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33. Monochromatic means: of a single amplitude of one polarization of one direction of a single frequency (wavelength) Answer: D) of a single frequency (wavelength)
Explanation: Coherent sources must be monochromatic. SLO P-11-D-14 · Understanding
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34. A string of length 2 m fixed at both ends vibrates in 4 loops. The wavelength is: 0.5 m 2 m 8 m 1 m Answer: D) 1 m
Explanation: Each loop is lambda2: lambda = 2Ln = 1 m. SLO P-11-D-10 · Application
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35. The microphone in noise-cancelling headphones is used to: record music measure temperature amplify the noise detect the incoming noise so an opposite wave can be generated Answer: D) detect the incoming noise so an opposite wave can be generated
Explanation: Feeds the processing circuit. SLO P-11-D-09 · Understanding
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36. Active noise control is also used in: aircraft cabins and car interiors X-ray machines microwave ovens telescopes Answer: A) aircraft cabins and car interiors
Explanation: To reduce engine noise. SLO P-11-D-09 · Understanding
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37. For interference, the waves from coherent sources should also have: different speeds different wavelengths similar amplitudes, for clear minima very different amplitudes Answer: C) similar amplitudes, for clear minima
Explanation: Good contrast. SLO P-11-D-14 · Understanding
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38. A tuning fork of 425 Hz resonates with a closed air column of length 20 cm (first resonance). The speed of sound is: 170 m/s 680 m/s 340 m/s 85 m/s Answer: C) 340 m/s
Explanation: lambda = 4L = 0.8 m; v = flambda = 340 m/s. SLO P-11-D-10 · Application
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39. For the same string (length 0.5 m, wave speed 200 m/s), the frequency of the third harmonic is: 600 Hz 200 Hz 800 Hz 400 Hz Answer: A) 600 Hz
Explanation: f3 = 3f1 = 3 200 = 600 Hz. SLO P-11-D-12 · Understanding
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40. The fundamental (first harmonic) of a string fixed at both ends has: an antinode at each end two loops one loop, with nodes at the ends no nodes Answer: C) one loop, with nodes at the ends
Explanation: L = lambda2. SLO P-11-D-12 · Understanding
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41. Diffraction is most noticeable when the gap width is: zero much larger than the wavelength about the same as the wavelength infinitely large Answer: C) about the same as the wavelength
Explanation: Significant spreading. SLO P-11-D-13 · Understanding
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42. The principle of superposition states that when two waves meet, the resultant displacement is: the product of the displacements the larger of the two displacements always zero the vector sum of the individual displacements Answer: D) the vector sum of the individual displacements
Explanation: Waves pass through each other unchanged afterwards. SLO P-11-D-07 · Application
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43. Two flutes play notes of 523 Hz and 527 Hz. The listener hears: two separate notes 4 beats per second at a pitch of about 525 Hz 1050 Hz 8 beats per second Answer: B) 4 beats per second at a pitch of about 525 Hz
Explanation: Beat frequency = difference; pitch = average. SLO P-11-D-16 · Application
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44. A pipe of length 0.34 m is closed at one end (v = 340 m/s, end correction ignored). Its fundamental frequency is: 250 Hz 500 Hz 125 Hz 750 Hz Answer: A) 250 Hz
Explanation: f1 = v4L = 250 Hz. SLO P-11-D-12 · Understanding
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45. For a tube closed at one end, the first resonance occurs when the length is: lambda2 lambda4 2lambda lambda Answer: B) lambda4
Explanation: Node at closed end, antinode at open end (end correction ignored). SLO P-11-D-10 · Application
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46. A stationary (standing) wave is formed when: one wave is reflected and absorbed a wave stops moving two waves of different frequencies meet two waves of the same frequency and amplitude travel in opposite directions and superpose Answer: D) two waves of the same frequency and amplitude travel in opposite directions and superpose
Explanation: Superposition of opposite travelling waves. SLO P-11-D-11 · Understanding
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47. In the tuning above, tightening slowed the beats, so the string's frequency was originally: 448 Hz 436 Hz (below 440 Hz) 440 Hz 444 Hz Answer: B) 436 Hz (below 440 Hz)
Explanation: Tightening raises frequency; it moved closer to 440 Hz from below. SLO P-11-D-16 · Application
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48. At a point, one wave alone gives a displacement of -2 cm and another alone gives -3 cm. When both arrive, the displacement is: -5 cm 3.61 cm 6 cm 1 cm Answer: A) -5 cm
Explanation: By superposition, displacements add: -2 + (-3) = -5 cm. SLO P-11-D-07 · Application
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49. A tabla player tightens the drum skin to remove beats with the harmonium. Tightening: lowers the pitch changes the speed of sound raises the drum's pitch has no effect Answer: C) raises the drum's pitch
Explanation: More tension, higher frequency. SLO P-11-D-16 · Application
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50. If the phase difference between two sources changes randomly, the interference pattern: becomes brighter changes so fast that no steady pattern is seen is unaffected becomes sharper Answer: B) changes so fast that no steady pattern is seen
Explanation: Average intensity becomes uniform. SLO P-11-D-14 · Understanding
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