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Superposition, Stationary Waves and Beats MCQs — Physics (page 2)

150 multiple-choice questions on Superposition, Stationary Waves and Beats from Physics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.

26. A guitarist plays the same note on two strings and hears 2 beats per second. This means:

  1. the strings are 2 Hz out of tune
  2. the strings are perfectly tuned
  3. one string is broken
  4. the strings are an octave apart

Answer: A) the strings are 2 Hz out of tune

Explanation: fb = f1 - f2. SLO P-11-D-16 · Application

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27. For destructive interference from in-phase sources, the path difference is:

  1. lambdan
  2. (n + tfrac12)lambda
  3. 2nlambda
  4. nlambda

Answer: B) (n + tfrac12)lambda

Explanation: Half-wavelength offsets. SLO P-11-D-08 · Understanding

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28. For effective cancellation, the delay in generating anti-noise must be:

  1. very small compared with the period of the noise
  2. exactly one second
  3. unimportant
  4. much longer than the period

Answer: A) very small compared with the period of the noise

Explanation: Otherwise the phase will be wrong. SLO P-11-D-09 · Understanding

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29. When an orchestra tunes before a concert, the oboe plays a reference A so that other players can:

  1. play louder
  2. change the speed of sound
  3. make faster beats
  4. eliminate beats with it

Answer: D) eliminate beats with it

Explanation: Tuning by beats. SLO P-11-D-16 · Application

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30. The beat frequency equals:

  1. the average of the frequencies
  2. the sum of the two frequencies
  3. the difference between the two frequencies
  4. the product of the frequencies

Answer: C) the difference between the two frequencies

Explanation: fb = f1 - f2. SLO P-11-D-15 · Understanding

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31. Superposition applies to:

  1. only water waves
  2. all types of waves
  3. only sound waves
  4. only light waves

Answer: B) all types of waves

Explanation: A general principle (for linear media). SLO P-11-D-07 · Application

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32. For the same string (length 0.8 m, wave speed 320 m/s), the frequency of the third harmonic is:

  1. 800 Hz
  2. 400 Hz
  3. 200 Hz
  4. 600 Hz

Answer: D) 600 Hz

Explanation: f3 = 3f1 = 3 200 = 600 Hz. SLO P-11-D-12 · Understanding

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33. Monochromatic means:

  1. of a single amplitude
  2. of one polarization
  3. of one direction
  4. of a single frequency (wavelength)

Answer: D) of a single frequency (wavelength)

Explanation: Coherent sources must be monochromatic. SLO P-11-D-14 · Understanding

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34. A string of length 2 m fixed at both ends vibrates in 4 loops. The wavelength is:

  1. 0.5 m
  2. 2 m
  3. 8 m
  4. 1 m

Answer: D) 1 m

Explanation: Each loop is lambda2: lambda = 2Ln = 1 m. SLO P-11-D-10 · Application

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35. The microphone in noise-cancelling headphones is used to:

  1. record music
  2. measure temperature
  3. amplify the noise
  4. detect the incoming noise so an opposite wave can be generated

Answer: D) detect the incoming noise so an opposite wave can be generated

Explanation: Feeds the processing circuit. SLO P-11-D-09 · Understanding

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36. Active noise control is also used in:

  1. aircraft cabins and car interiors
  2. X-ray machines
  3. microwave ovens
  4. telescopes

Answer: A) aircraft cabins and car interiors

Explanation: To reduce engine noise. SLO P-11-D-09 · Understanding

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37. For interference, the waves from coherent sources should also have:

  1. different speeds
  2. different wavelengths
  3. similar amplitudes, for clear minima
  4. very different amplitudes

Answer: C) similar amplitudes, for clear minima

Explanation: Good contrast. SLO P-11-D-14 · Understanding

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38. A tuning fork of 425 Hz resonates with a closed air column of length 20 cm (first resonance). The speed of sound is:

  1. 170 m/s
  2. 680 m/s
  3. 340 m/s
  4. 85 m/s

Answer: C) 340 m/s

Explanation: lambda = 4L = 0.8 m; v = flambda = 340 m/s. SLO P-11-D-10 · Application

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39. For the same string (length 0.5 m, wave speed 200 m/s), the frequency of the third harmonic is:

  1. 600 Hz
  2. 200 Hz
  3. 800 Hz
  4. 400 Hz

Answer: A) 600 Hz

Explanation: f3 = 3f1 = 3 200 = 600 Hz. SLO P-11-D-12 · Understanding

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40. The fundamental (first harmonic) of a string fixed at both ends has:

  1. an antinode at each end
  2. two loops
  3. one loop, with nodes at the ends
  4. no nodes

Answer: C) one loop, with nodes at the ends

Explanation: L = lambda2. SLO P-11-D-12 · Understanding

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41. Diffraction is most noticeable when the gap width is:

  1. zero
  2. much larger than the wavelength
  3. about the same as the wavelength
  4. infinitely large

Answer: C) about the same as the wavelength

Explanation: Significant spreading. SLO P-11-D-13 · Understanding

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42. The principle of superposition states that when two waves meet, the resultant displacement is:

  1. the product of the displacements
  2. the larger of the two displacements
  3. always zero
  4. the vector sum of the individual displacements

Answer: D) the vector sum of the individual displacements

Explanation: Waves pass through each other unchanged afterwards. SLO P-11-D-07 · Application

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43. Two flutes play notes of 523 Hz and 527 Hz. The listener hears:

  1. two separate notes
  2. 4 beats per second at a pitch of about 525 Hz
  3. 1050 Hz
  4. 8 beats per second

Answer: B) 4 beats per second at a pitch of about 525 Hz

Explanation: Beat frequency = difference; pitch = average. SLO P-11-D-16 · Application

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44. A pipe of length 0.34 m is closed at one end (v = 340 m/s, end correction ignored). Its fundamental frequency is:

  1. 250 Hz
  2. 500 Hz
  3. 125 Hz
  4. 750 Hz

Answer: A) 250 Hz

Explanation: f1 = v4L = 250 Hz. SLO P-11-D-12 · Understanding

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45. For a tube closed at one end, the first resonance occurs when the length is:

  1. lambda2
  2. lambda4
  3. 2lambda
  4. lambda

Answer: B) lambda4

Explanation: Node at closed end, antinode at open end (end correction ignored). SLO P-11-D-10 · Application

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46. A stationary (standing) wave is formed when:

  1. one wave is reflected and absorbed
  2. a wave stops moving
  3. two waves of different frequencies meet
  4. two waves of the same frequency and amplitude travel in opposite directions and superpose

Answer: D) two waves of the same frequency and amplitude travel in opposite directions and superpose

Explanation: Superposition of opposite travelling waves. SLO P-11-D-11 · Understanding

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47. In the tuning above, tightening slowed the beats, so the string's frequency was originally:

  1. 448 Hz
  2. 436 Hz (below 440 Hz)
  3. 440 Hz
  4. 444 Hz

Answer: B) 436 Hz (below 440 Hz)

Explanation: Tightening raises frequency; it moved closer to 440 Hz from below. SLO P-11-D-16 · Application

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48. At a point, one wave alone gives a displacement of -2 cm and another alone gives -3 cm. When both arrive, the displacement is:

  1. -5 cm
  2. 3.61 cm
  3. 6 cm
  4. 1 cm

Answer: A) -5 cm

Explanation: By superposition, displacements add: -2 + (-3) = -5 cm. SLO P-11-D-07 · Application

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49. A tabla player tightens the drum skin to remove beats with the harmonium. Tightening:

  1. lowers the pitch
  2. changes the speed of sound
  3. raises the drum's pitch
  4. has no effect

Answer: C) raises the drum's pitch

Explanation: More tension, higher frequency. SLO P-11-D-16 · Application

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50. If the phase difference between two sources changes randomly, the interference pattern:

  1. becomes brighter
  2. changes so fast that no steady pattern is seen
  3. is unaffected
  4. becomes sharper

Answer: B) changes so fast that no steady pattern is seen

Explanation: Average intensity becomes uniform. SLO P-11-D-14 · Understanding

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