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Superposition, Stationary Waves and Beats MCQs — Physics (page 4)

150 multiple-choice questions on Superposition, Stationary Waves and Beats from Physics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.

76. Two identical waves interfere constructively. The resultant intensity is:

  1. 4 times that of one wave
  2. zero
  3. 2 times
  4. the same

Answer: A) 4 times that of one wave

Explanation: Amplitude doubles; I propto A^2. SLO P-11-D-08 · Understanding

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77. Noise cancellation works best for:

  1. sudden, high-frequency sounds
  2. speech only
  3. music only
  4. steady, low-frequency sounds such as engine hum

Answer: D) steady, low-frequency sounds such as engine hum

Explanation: Predictable, long-wavelength noise is easier to cancel. SLO P-11-D-09 · Understanding

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78. A pipe of length 0.85 m is closed at one end (v = 340 m/s, end correction ignored). Its fundamental frequency is:

  1. 300 Hz
  2. 50 Hz
  3. 100 Hz
  4. 200 Hz

Answer: C) 100 Hz

Explanation: f1 = v4L = 100 Hz. SLO P-11-D-12 · Understanding

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79. If the anti-noise wave has a smaller amplitude than the noise, the result is:

  1. complete silence
  2. louder noise
  3. partial cancellation (quieter noise)
  4. no sound at all

Answer: C) partial cancellation (quieter noise)

Explanation: Resultant amplitude = An - Aa. SLO P-11-D-09 · Understanding

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80. Increasing the tension in a guitar string makes its frequency:

  1. increase
  2. stay the same
  3. zero
  4. decrease

Answer: A) increase

Explanation: v = T/mu increases. SLO P-11-D-16 · Application

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81. A stationary wave does not:

  1. transfer energy along the medium
  2. have a frequency
  3. have nodes
  4. have antinodes

Answer: A) transfer energy along the medium

Explanation: Energy is stored, not transported. SLO P-11-D-11 · Understanding

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82. When two notes are exactly in tune, the beat frequency is:

  1. infinite
  2. equal to the note frequency
  3. maximum
  4. zero

Answer: D) zero

Explanation: No difference in frequency. SLO P-11-D-15 · Understanding

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83. A harbour wall gap 5 m wide is approached by sea waves of wavelength 5 m. The waves inside the harbour will:

  1. spread out widely
  2. double in height
  3. stop
  4. travel straight with no spreading

Answer: A) spread out widely

Explanation: Gap ≈ wavelength. SLO P-11-D-13 · Understanding

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84. Two coherent waves of amplitudes 6 mm and 2 mm meet. The maximum and minimum possible resultant amplitudes are:

  1. 6 mm and 2 mm
  2. 12 mm and 4 mm
  3. 8 mm and 4 mm
  4. 6.32 mm and 0 mm

Answer: C) 8 mm and 4 mm

Explanation: In phase: 6 + 2 = 8 mm; in antiphase: 6 - 2 = 4 mm. SLO P-11-D-07 · Application

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85. Constructive interference occurs when two waves meet:

  1. at right angles
  2. in phase (crest on crest)
  3. in antiphase (crest on trough)
  4. with different frequencies

Answer: B) in phase (crest on crest)

Explanation: Amplitudes add. SLO P-11-D-08 · Understanding

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86. Two sources are coherent if they have:

  1. the same frequency and a constant phase difference
  2. different frequencies
  3. the same amplitude only
  4. random phases

Answer: A) the same frequency and a constant phase difference

Explanation: Needed for a stable interference pattern. SLO P-11-D-14 · Understanding

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87. In a stretched-string experiment, increasing the frequency of the vibrator (same tension) produces:

  1. a travelling wave only
  2. fewer loops
  3. no change
  4. more loops on the string

Answer: D) more loops on the string

Explanation: Higher harmonics fit more half-wavelengths. SLO P-11-D-10 · Application

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88. A closed tube resonates first at 20 cm and next at 60 cm. The wavelength is:

  1. 40 cm
  2. 80 cm
  3. 20 cm
  4. 120 cm

Answer: B) 80 cm

Explanation: Successive resonances differ by lambda2 = 40 cm. SLO P-11-D-10 · Application

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89. Bright fringes in Young's double-slit experiment are due to:

  1. polarization
  2. destructive interference
  3. reflection
  4. constructive interference

Answer: D) constructive interference

Explanation: Path difference nlambda. SLO P-11-D-08 · Understanding

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90. The distance between a node and the next antinode is:

  1. lambda
  2. lambda2
  3. lambda4
  4. 2lambda

Answer: C) lambda4

Explanation: Half of node–node spacing. SLO P-11-D-11 · Understanding

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91. At a point, one wave alone gives a displacement of 5 cm and another alone gives -3 cm. When both arrive, the displacement is:

  1. 8 cm
  2. 2 cm
  3. -15 cm
  4. 5.83 cm

Answer: B) 2 cm

Explanation: By superposition, displacements add: 5 + (-3) = 2 cm. SLO P-11-D-07 · Application

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92. All particles between two adjacent nodes of a stationary wave vibrate:

  1. with a phase difference of 90^circ
  2. in antiphase
  3. in phase with each other
  4. randomly

Answer: C) in phase with each other

Explanation: They move up and down together. SLO P-11-D-11 · Understanding

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93. Two coherent sources in phase emit waves of wavelength lambda. At a point, the path difference is 1.5lambda. The interference there is:

  1. neither — there is no interference
  2. constructive
  3. destructive
  4. constructive only for sound

Answer: C) destructive

Explanation: Path difference = nlambda gives constructive; (n + 12)lambda gives destructive. Here 1.5lambda ⇒ destructive. SLO P-11-D-07 · Application

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94. The amplitude of a stationary wave:

  1. varies from zero at nodes to a maximum at antinodes
  2. increases along the string
  3. is the same everywhere
  4. is zero everywhere

Answer: A) varies from zero at nodes to a maximum at antinodes

Explanation: Unlike a progressive wave. SLO P-11-D-11 · Understanding

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95. Twice per cycle, a stretched string carrying a stationary wave is:

  1. broken
  2. momentarily straight (all displacements zero)
  3. still at nodes only
  4. at maximum displacement everywhere

Answer: B) momentarily straight (all displacements zero)

Explanation: Graphically, the two travelling waves cancel at that instant. SLO P-11-D-11 · Understanding

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96. Guitar players can use 'harmonics' and beats to tune adjacent strings because:

  1. harmonics have no frequency
  2. harmonics are louder
  3. matching harmonics give zero beats when in tune
  4. beats make strings longer

Answer: C) matching harmonics give zero beats when in tune

Explanation: Compare equal frequencies. SLO P-11-D-16 · Application

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97. At the fixed end of a stretched string there is always:

  1. an antinode
  2. a node
  3. zero tension
  4. maximum amplitude

Answer: B) a node

Explanation: The end cannot move. SLO P-11-D-11 · Understanding

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98. Two coherent waves of amplitudes 3 mm and 5 mm meet. The maximum and minimum possible resultant amplitudes are:

  1. 5 mm and 3 mm
  2. 8 mm and 2 mm
  3. 5.83 mm and 0 mm
  4. 15 mm and 2 mm

Answer: B) 8 mm and 2 mm

Explanation: In phase: 3 + 5 = 8 mm; in antiphase: 3 - 5 = 2 mm. SLO P-11-D-07 · Application

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99. In a resonance tube (air column) experiment, a loud sound is heard when:

  1. the tuning fork stops
  2. the tube is empty
  3. a stationary wave forms in the air column (resonance)
  4. the water boils

Answer: C) a stationary wave forms in the air column (resonance)

Explanation: Length matches a harmonic. SLO P-11-D-10 · Application

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100. In the microwave experiment, the detector is moved along the line between transmitter and reflector. It shows:

  1. a constant reading
  2. only minima
  3. alternating maxima (antinodes) and minima (nodes)
  4. only maxima

Answer: C) alternating maxima (antinodes) and minima (nodes)

Explanation: Stationary wave pattern. SLO P-11-D-10 · Application

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