MCQs / Physics / Superposition, Stationary Waves and Beats

Superposition, Stationary Waves and Beats MCQs — Physics (page 5)

150 multiple-choice questions on Superposition, Stationary Waves and Beats from Physics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.

101. A tuning fork of 400 Hz and an unknown fork give 3 beats/s. The unknown frequency is:

  1. 1200 Hz
  2. 133 Hz
  3. 397 Hz or 403 Hz
  4. exactly 403 Hz

Answer: C) 397 Hz or 403 Hz

Explanation: f = 400 pm 3. SLO P-11-D-15 · Understanding

Discuss this question

102. A node in a stationary wave is a point of:

  1. zero amplitude (no displacement)
  2. maximum amplitude
  3. maximum speed
  4. maximum energy flow

Answer: A) zero amplitude (no displacement)

Explanation: Waves always cancel there. SLO P-11-D-11 · Understanding

Discuss this question

103. Destructive interference occurs when two waves meet:

  1. in antiphase (crest on trough)
  2. at the same speed only
  3. with zero amplitude
  4. in phase

Answer: A) in antiphase (crest on trough)

Explanation: Amplitudes subtract. SLO P-11-D-08 · Understanding

Discuss this question

104. A sound wave and its exact inverted copy add to give:

  1. a wave of double frequency
  2. zero displacement everywhere
  3. a stationary wave
  4. double displacement

Answer: B) zero displacement everywhere

Explanation: Complete destructive interference. SLO P-11-D-09 · Understanding

Discuss this question

105. We can hear people round a corner but cannot see them because:

  1. sound wavelengths are similar to doorway sizes but light wavelengths are tiny
  2. light cannot travel round corners at all
  3. sound travels faster than light
  4. sound is transverse

Answer: A) sound wavelengths are similar to doorway sizes but light wavelengths are tiny

Explanation: Sound diffracts much more. SLO P-11-D-13 · Understanding

Discuss this question

106. Two tuning forks of 100 Hz and 102 Hz are sounded together. The number of beats heard per second is:

  1. 3
  2. 101
  3. 1.5
  4. 202

Answer: C) 1.5

Explanation: Beat frequency = f1 - f2 = 1.5 Hz. SLO P-11-D-15 · Understanding

Discuss this question

107. A pipe closed at one end produces only:

  1. even harmonics
  2. the fundamental only
  3. odd harmonics (1 : 3 : 5 …)
  4. all harmonics

Answer: C) odd harmonics (1 : 3 : 5 …)

Explanation: Node at closed end, antinode at open end. SLO P-11-D-12 · Understanding

Discuss this question

108. A progressive wave differs from a stationary wave because in a progressive wave:

  1. all points have the same amplitude and energy is transferred
  2. no energy is transferred
  3. there are nodes and antinodes
  4. the wave does not move

Answer: A) all points have the same amplitude and energy is transferred

Explanation: Key comparison. SLO P-11-D-11 · Understanding

Discuss this question

109. In a region of destructive interference, the wave energy:

  1. is destroyed
  2. is redistributed to regions of constructive interference
  3. is created elsewhere
  4. turns into heat only

Answer: B) is redistributed to regions of constructive interference

Explanation: Energy is conserved. SLO P-11-D-08 · Understanding

Discuss this question

110. Why don't noise-cancelling headphones cancel the music you're listening to?

  1. the music is polarized
  2. the circuit only generates anti-noise for the outside sound picked up by the microphone
  3. music is a different kind of wave
  4. music travels faster

Answer: B) the circuit only generates anti-noise for the outside sound picked up by the microphone

Explanation: The music signal is added separately. SLO P-11-D-09 · Understanding

Discuss this question

111. Two separate light bulbs do not produce a visible interference pattern because they are:

  1. polarized
  2. too far apart
  3. too bright
  4. not coherent

Answer: D) not coherent

Explanation: Their phase difference changes randomly. SLO P-11-D-14 · Understanding

Discuss this question

112. Diffraction of waves provides evidence that light is:

  1. longitudinal
  2. a particle only
  3. a sound wave
  4. a wave

Answer: D) a wave

Explanation: Only waves diffract. SLO P-11-D-13 · Understanding

Discuss this question

113. A piano tuner tightens a string while sounding it with a 440 Hz fork. The beats slow from 4 Hz to 2 Hz. The string's frequency is now:

  1. 438 Hz or 442 Hz
  2. 444 Hz only
  3. 880 Hz
  4. exactly 440 Hz

Answer: A) 438 Hz or 442 Hz

Explanation: Still 2 Hz from 440 Hz. SLO P-11-D-16 · Application

Discuss this question

114. Which condition is needed for a stable interference pattern?

  1. the sources must be very bright
  2. the waves must be longitudinal
  3. the sources must be different colours
  4. the sources must be coherent

Answer: D) the sources must be coherent

Explanation: Constant phase difference. SLO P-11-D-08 · Understanding

Discuss this question

115. A string of length 0.5 m fixed at both ends carries waves at 200 m/s. Its fundamental frequency is:

  1. 800 Hz
  2. 200 Hz
  3. 400 Hz
  4. 100 Hz

Answer: B) 200 Hz

Explanation: f1 = v2L = 2002(0.5) = 200 Hz. SLO P-11-D-12 · Understanding

Discuss this question

116. Two tuning forks of 330 Hz and 335 Hz are sounded together. The number of beats heard per second is:

  1. 665
  2. 5
  3. 332
  4. 10

Answer: B) 5

Explanation: Beat frequency = f1 - f2 = 5 Hz. SLO P-11-D-15 · Understanding

Discuss this question

117. Two coherent waves of amplitudes 4 mm and 4 mm meet. The maximum and minimum possible resultant amplitudes are:

  1. 8 mm and 4 mm
  2. 16 mm and 0 mm
  3. 4 mm and 4 mm
  4. 8 mm and 0 mm

Answer: D) 8 mm and 0 mm

Explanation: In phase: 4 + 4 = 8 mm; in antiphase: 4 - 4 = 0 mm. SLO P-11-D-07 · Application

Discuss this question

118. Beats are an example of interference in:

  1. time (at one place)
  2. space only
  3. polarization
  4. diffraction

Answer: A) time (at one place)

Explanation: Phase difference changes with time. SLO P-11-D-15 · Understanding

Discuss this question

119. For constructive interference, the phase difference is:

  1. any value
  2. 0, 2pi, 4pi, ldots
  3. pi2
  4. pi, 3pi, 5pi, ldots

Answer: B) 0, 2pi, 4pi, ldots

Explanation: Whole cycles. SLO P-11-D-08 · Understanding

Discuss this question

120. Two coherent sources in phase emit waves of wavelength lambda. At a point, the path difference is 0.5lambda. The interference there is:

  1. neither — there is no interference
  2. constructive
  3. constructive only for sound
  4. destructive

Answer: D) destructive

Explanation: Path difference = nlambda gives constructive; (n + 12)lambda gives destructive. Here 0.5lambda ⇒ destructive. SLO P-11-D-07 · Application

Discuss this question

121. Two coherent sources in phase emit waves of wavelength lambda. At a point, the path difference is 2lambda. The interference there is:

  1. constructive only for sound
  2. neither — there is no interference
  3. destructive
  4. constructive

Answer: D) constructive

Explanation: Path difference = nlambda gives constructive; (n + 12)lambda gives destructive. Here 2lambda ⇒ constructive. SLO P-11-D-07 · Application

Discuss this question

122. For the second harmonic of a string, the number of loops is:

  1. 1
  2. 2
  3. 3
  4. 4

Answer: B) 2

Explanation: L = lambda. SLO P-11-D-12 · Understanding

Discuss this question

123. Noise-cancelling headphones need a battery because:

  1. electronic circuits must process the noise and drive the speakers
  2. they use magnets only
  3. the sound waves need charging
  4. they heat the ear

Answer: A) electronic circuits must process the noise and drive the speakers

Explanation: Active system. SLO P-11-D-09 · Understanding

Discuss this question

124. Walking past two loudspeakers playing the same note, you hear:

  1. a constant loudness
  2. silence everywhere
  3. a changing pitch
  4. alternate loud and quiet regions

Answer: D) alternate loud and quiet regions

Explanation: Interference pattern. SLO P-11-D-08 · Understanding

Discuss this question

125. Microwaves from one transmitter passing through two slits act as:

  1. two incoherent sources
  2. two coherent sources
  3. longitudinal waves
  4. one incoherent source

Answer: B) two coherent sources

Explanation: Double-slit with microwaves. SLO P-11-D-14 · Understanding

Discuss this question

Previous Page 5 of 6 Next

Practise Superposition, Stationary Waves and Beats MCQs

More Physics chapters