26. The three-figure bearing of due south is:
- 180^circ
- 315^circ
- 225^circ
- 135^circ
Answer: A) 180^circ
Explanation: Bearings are measured clockwise from north: N = 000^circ, E = 090^circ, S = 180^circ, W = 270^circ. SLO M-09-B-25 · Knowledge
MCQs / Mathematics / Bearing
63 multiple-choice questions on Bearing from Mathematics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.
Answer: A) 180^circ
Explanation: Bearings are measured clockwise from north: N = 000^circ, E = 090^circ, S = 180^circ, W = 270^circ. SLO M-09-B-25 · Knowledge
Answer: B) 90^circ
Explanation: 130^circ - 40^circ = 90^circ. SLO M-09-B-26 · Understanding
Answer: B) 030^circ
Explanation: Add 60^circ: 030^circ (keeping the answer between 000^circ and 360^circ). SLO M-09-B-26 · Understanding
Answer: B) 50 km
Explanation: 30^2 + 40^2 = 50 km. SLO M-09-B-27 · Application
Answer: B) 90^circ clockwise
Explanation: 190^circ - 100^circ = 90^circ clockwise. SLO M-09-B-26 · Understanding
Answer: C) 155^circ
Explanation: Subtract 45^circ: 155^circ (keeping the answer between 000^circ and 360^circ). SLO M-09-B-26 · Understanding
Answer: B) 25 km on a bearing of about 016.3^circ
Explanation: Distance = 24^2 + 7^2 = 25 km. Bearing = tan^-1 724 approx 16.3^circ (measured from north). SLO M-09-B-27 · Application
Answer: D) 5 3 km
Explanation: The angle from the north–south line is 60^circ, so east = 10sin 60^circ = 10 32 = 5 3 km (and it is 5 km north). SLO M-09-B-27 · Application
Answer: A) 13 km on a bearing of about 067.4^circ
Explanation: Distance = 5^2 + 12^2 = 13 km. Bearing = tan^-1 125 approx 67.4^circ (measured from north). SLO M-09-B-27 · Application
Answer: D) 14 km
Explanation: North = 14 2 cos 45^circ = 14 2 1 2 = 14 km. SLO M-09-B-27 · Application
Answer: D) 310^circ
Explanation: Back bearing = 130^circ + 180^circ = 310^circ. SLO M-09-B-26 · Understanding
Answer: D) 4 3 km
Explanation: The angle from the south–south line is 60^circ, so east = 8sin 60^circ = 8 32 = 4 3 km (and it is 4 km south). SLO M-09-B-27 · Application
Answer: C) 225^circ
Explanation: From start the finish is on 045^circ; the back bearing is 045^circ + 180^circ = 225^circ. SLO M-09-B-26 · Understanding
Answer: A) 15 km
Explanation: The angle between the bearings is 120^circ - 30^circ = 90^circ, so the distance is 9^2 + 12^2 = 15 km. SLO M-09-B-27 · Application
Answer: B) 500 m
Explanation: East 400 m and north 300 m: 400^2 + 300^2 = 500 m. SLO M-09-B-27 · Application
Answer: D) 000^circ
Explanation: Measure clockwise from north (the positive y-axis): 000^circ. SLO M-09-B-26 · Understanding
Answer: A) 10 km
Explanation: The angle from the north–south line is 30^circ, so east = 20sin 30^circ = 20 12 = 10 km (and it is 10 3 km north). SLO M-09-B-27 · Application
Answer: A) 000^circ
Explanation: North is the starting direction, 000^circ. SLO M-09-B-25 · Knowledge
Answer: B) 200^circ
Explanation: Start at north and turn clockwise: S,20^circ, W = 200^circ. SLO M-09-B-25 · Knowledge
Answer: A) 270^circ
Explanation: The ship is due west of the lighthouse. SLO M-09-B-26 · Understanding
Answer: D) 120^circ
Explanation: Back bearing = 300^circ - 180^circ = 120^circ. SLO M-09-B-26 · Understanding
Answer: A) 225^circ
Explanation: Bearings are measured clockwise from north: N = 000^circ, E = 090^circ, S = 180^circ, W = 270^circ. SLO M-09-B-25 · Knowledge
Answer: B) 045^circ
Explanation: Bearings are measured clockwise from north: N = 000^circ, E = 090^circ, S = 180^circ, W = 270^circ. SLO M-09-B-25 · Knowledge
Answer: C) 075^circ
Explanation: A bearing always has three figures, so 75^circ is written 075^circ. SLO M-09-B-25 · Knowledge
Answer: C) 300^circ
Explanation: Subtract 100^circ: 300^circ (keeping the answer between 000^circ and 360^circ). SLO M-09-B-26 · Understanding