MCQs / Physics / Circular and Rotational Motion
Circular and Rotational Motion MCQs — Physics (page 4) 186 multiple-choice questions on Circular and Rotational Motion from Physics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.
76. A solid sphere of mass 5 kg and radius 0.2 m has I = 25MR^2 = 0.2 kg m^2 0.08 kg m^2 0.4 kg m^2 0.04 kg m^2 Answer: B) 0.08 kg m^2
Explanation: 25 5 0.04 = 0.08 kg m^2. SLO P-11-B-18 · Application
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77. A wheel turns at 60 revolutions per minute. Its angular velocity is: 12.6 rad/s 6.28 rad/s 1 rad/s 3.14 rad/s Answer: B) 6.28 rad/s
Explanation: omega = 2pi f = 2pi 6060 = 6.28 rad/s. SLO P-11-B-08 · Understanding
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78. The true weight of an astronaut in orbit is: infinite equal to their mass exactly zero not zero — gravity still acts on them Answer: D) not zero — gravity still acts on them
Explanation: Weightlessness is only apparent. SLO P-11-B-16 · Understanding
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79. If a satellite's speed were too small for its orbit, it would: fly off into space stay in the same orbit spiral or fall towards the Earth stop in space Answer: C) spiral or fall towards the Earth
Explanation: Gravity would exceed the required centripetal force. SLO P-11-B-16 · Understanding
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80. A wheel starts at 5 rad/s with angular acceleration 0.5 rad/s^2. After 20 s its angular velocity is: 7.5 rad/s 15 rad/s 30 rad/s 11 rad/s Answer: B) 15 rad/s
Explanation: omegaf = omegai + alpha t = 5 + (0.5)(20) = 15 rad/s. SLO P-11-B-09 · Application
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81. A bucket of water is swung in a vertical circle of radius 0.4 m. The minimum speed at the top so the water stays in is (g = 9.8 m/s^2): 1.98 m/s 0.99 m/s 3.96 m/s 2.8 m/s Answer: A) 1.98 m/s
Explanation: At the minimum speed, weight alone provides the centripetal force: mg = mv^2r Rightarrow v = gr = 1.98 m/s. SLO P-11-B-15 · Application
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82. In uniform circular motion, which quantity is constant? velocity speed acceleration vector momentum vector Answer: B) speed
Explanation: Magnitudes are constant; directions keep changing. SLO P-11-B-10 · Understanding
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83. A disc's angular velocity changes from 10 rad/s to 40 rad/s in 5 s. Its angular acceleration is: 3 rad/s^2 12 rad/s^2 -6 rad/s^2 6 rad/s^2 Answer: D) 6 rad/s^2
Explanation: alpha = omegaf - omegait = 6 rad/s^2. SLO P-11-B-08 · Understanding
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84. A centrifuge tube is 0.15 m from the axis and spins at 6000 rpm. The centripetal acceleration is about how many times g (g = 9.8)? 12,100 g 3020 g 9.62 g 6040 g Answer: D) 6040 g
Explanation: omega = 628 rad/s; a = romega^2 = 59,200 m/s^2 approx 6040g. SLO P-11-B-21 · Application
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85. When a cyclist leans into a bend, the inward force comes from: friction on the tyres (with the normal reaction balancing weight) the cyclist's muscles pushing outward gravity alone the bicycle's speed Answer: A) friction on the tyres (with the normal reaction balancing weight)
Explanation: Friction acts towards the centre of the bend. SLO P-11-B-10 · Understanding
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86. A flywheel stores energy as: heat chemical energy elastic energy rotational kinetic energy Answer: D) rotational kinetic energy
Explanation: E = 12Iomega^2. SLO P-11-B-20 · Application
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87. A space station is a ring of radius 100 m. To produce artificial gravity of 9.8 m/s^2 at the rim, it must rotate at: 0.626 rad/s 0.098 rad/s 0.157 rad/s 0.313 rad/s Answer: D) 0.313 rad/s
Explanation: romega^2 = g Rightarrow omega = g/r = 9.8/100 = 0.313 rad/s. SLO P-11-B-17 · Understanding
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88. 60^circ expressed in radians is: 3pi 2pi3 pi3 pi6 Answer: C) pi3
Explanation: Multiply by pi180^circ: 60 pi180 = pi3 rad. SLO P-11-B-07 · Understanding
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89. A gyroscope keeps its axis pointing in a fixed direction because: friction holds it its large angular momentum resists changes in direction it has no mass gravity is zero Answer: B) its large angular momentum resists changes in direction
Explanation: Changing vecL needs a torque. SLO P-11-B-20 · Application
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90. An ice skater with I = 2 kg m^2 spins at 10 rad/s, then pulls in her arms so I = 5 kg m^2. Her new angular velocity is: 8 rad/s 25 rad/s 4 rad/s 2 rad/s Answer: C) 4 rad/s
Explanation: I1omega1 = I2omega2 Rightarrow omega2 = 2 105 = 4 rad/s. SLO P-11-B-20 · Application
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91. An ice skater with I = 6 kg m^2 spins at 3 rad/s, then pulls in her arms so I = 2 kg m^2. Her new angular velocity is: 9 rad/s 4.5 rad/s 18 rad/s 1 rad/s Answer: A) 9 rad/s
Explanation: I1omega1 = I2omega2 Rightarrow omega2 = 6 32 = 9 rad/s. SLO P-11-B-20 · Application
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92. If the radius is doubled at the same speed, the centripetal force becomes: twice as large 4 times as large half as large unchanged Answer: C) half as large
Explanation: F propto 1/r. SLO P-11-B-14 · Application
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93. Angular momentum is conserved when: no external torque acts the body is at rest no external force acts kinetic energy is conserved Answer: A) no external torque acts
Explanation: tau = Delta LDelta t; zero torque means constant L. SLO P-11-B-20 · Application
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94. Cream is separated from milk in a dairy centrifuge because: cream is less dense and stays nearer the axis cream is magnetic cream boils faster cream is denser Answer: A) cream is less dense and stays nearer the axis
Explanation: Lighter components move inward relative to denser ones. SLO P-11-B-21 · Application
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95. At the axis of a rotating space station, an astronaut would feel: pulled outward strongly double gravity full Earth gravity weightless Answer: D) weightless
Explanation: r = 0 Rightarrow a = 0. SLO P-11-B-17 · Understanding
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96. The Earth's angular momentum about its axis stays nearly constant because: it is not rotating gravity keeps it constant it has no mass external torques on it are very small Answer: D) external torques on it are very small
Explanation: Hence the steady length of the day. SLO P-11-B-20 · Application
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97. A fan running at 30 rad/s is switched off and stops uniformly in 10 s. The number of revolutions it makes while stopping is about: 4.8 47.7 150 23.9 Answer: D) 23.9
Explanation: theta = omegai + omegaf2t = 15 10 = 150 rad = 1502pi approx 23.9 rev. SLO P-11-B-09 · Application
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98. The ideal banking angle of a curve with r = 100 m for v = 20 m/s (g = 10) satisfies tantheta = 0.4 0.2 4 2.5 Answer: A) 0.4
Explanation: tantheta = v^2rg = 4001000 = 0.4. SLO P-11-B-15 · Application
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99. One complete revolution equals: 2pi rad pi rad 1 rad 360 rad Answer: A) 2pi rad
Explanation: 360^circ = 2pi rad. SLO P-11-B-07 · Understanding
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100. 180^circ expressed in radians is: pi 2pi 3pi pi2 Answer: A) pi
Explanation: Multiply by pi180^circ: 180 pi180 = pi rad. SLO P-11-B-07 · Understanding
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