MCQs / Physics / Circular and Rotational Motion

Circular and Rotational Motion MCQs — Physics (page 4)

186 multiple-choice questions on Circular and Rotational Motion from Physics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.

76. A solid sphere of mass 5 kg and radius 0.2 m has I = 25MR^2 =

  1. 0.2 kg m^2
  2. 0.08 kg m^2
  3. 0.4 kg m^2
  4. 0.04 kg m^2

Answer: B) 0.08 kg m^2

Explanation: 25 5 0.04 = 0.08 kg m^2. SLO P-11-B-18 · Application

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77. A wheel turns at 60 revolutions per minute. Its angular velocity is:

  1. 12.6 rad/s
  2. 6.28 rad/s
  3. 1 rad/s
  4. 3.14 rad/s

Answer: B) 6.28 rad/s

Explanation: omega = 2pi f = 2pi 6060 = 6.28 rad/s. SLO P-11-B-08 · Understanding

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78. The true weight of an astronaut in orbit is:

  1. infinite
  2. equal to their mass
  3. exactly zero
  4. not zero — gravity still acts on them

Answer: D) not zero — gravity still acts on them

Explanation: Weightlessness is only apparent. SLO P-11-B-16 · Understanding

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79. If a satellite's speed were too small for its orbit, it would:

  1. fly off into space
  2. stay in the same orbit
  3. spiral or fall towards the Earth
  4. stop in space

Answer: C) spiral or fall towards the Earth

Explanation: Gravity would exceed the required centripetal force. SLO P-11-B-16 · Understanding

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80. A wheel starts at 5 rad/s with angular acceleration 0.5 rad/s^2. After 20 s its angular velocity is:

  1. 7.5 rad/s
  2. 15 rad/s
  3. 30 rad/s
  4. 11 rad/s

Answer: B) 15 rad/s

Explanation: omegaf = omegai + alpha t = 5 + (0.5)(20) = 15 rad/s. SLO P-11-B-09 · Application

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81. A bucket of water is swung in a vertical circle of radius 0.4 m. The minimum speed at the top so the water stays in is (g = 9.8 m/s^2):

  1. 1.98 m/s
  2. 0.99 m/s
  3. 3.96 m/s
  4. 2.8 m/s

Answer: A) 1.98 m/s

Explanation: At the minimum speed, weight alone provides the centripetal force: mg = mv^2r Rightarrow v = gr = 1.98 m/s. SLO P-11-B-15 · Application

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82. In uniform circular motion, which quantity is constant?

  1. velocity
  2. speed
  3. acceleration vector
  4. momentum vector

Answer: B) speed

Explanation: Magnitudes are constant; directions keep changing. SLO P-11-B-10 · Understanding

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83. A disc's angular velocity changes from 10 rad/s to 40 rad/s in 5 s. Its angular acceleration is:

  1. 3 rad/s^2
  2. 12 rad/s^2
  3. -6 rad/s^2
  4. 6 rad/s^2

Answer: D) 6 rad/s^2

Explanation: alpha = omegaf - omegait = 6 rad/s^2. SLO P-11-B-08 · Understanding

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84. A centrifuge tube is 0.15 m from the axis and spins at 6000 rpm. The centripetal acceleration is about how many times g (g = 9.8)?

  1. 12,100 g
  2. 3020 g
  3. 9.62 g
  4. 6040 g

Answer: D) 6040 g

Explanation: omega = 628 rad/s; a = romega^2 = 59,200 m/s^2 approx 6040g. SLO P-11-B-21 · Application

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85. When a cyclist leans into a bend, the inward force comes from:

  1. friction on the tyres (with the normal reaction balancing weight)
  2. the cyclist's muscles pushing outward
  3. gravity alone
  4. the bicycle's speed

Answer: A) friction on the tyres (with the normal reaction balancing weight)

Explanation: Friction acts towards the centre of the bend. SLO P-11-B-10 · Understanding

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86. A flywheel stores energy as:

  1. heat
  2. chemical energy
  3. elastic energy
  4. rotational kinetic energy

Answer: D) rotational kinetic energy

Explanation: E = 12Iomega^2. SLO P-11-B-20 · Application

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87. A space station is a ring of radius 100 m. To produce artificial gravity of 9.8 m/s^2 at the rim, it must rotate at:

  1. 0.626 rad/s
  2. 0.098 rad/s
  3. 0.157 rad/s
  4. 0.313 rad/s

Answer: D) 0.313 rad/s

Explanation: romega^2 = g Rightarrow omega = g/r = 9.8/100 = 0.313 rad/s. SLO P-11-B-17 · Understanding

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88. 60^circ expressed in radians is:

  1. 3pi
  2. 2pi3
  3. pi3
  4. pi6

Answer: C) pi3

Explanation: Multiply by pi180^circ: 60 pi180 = pi3 rad. SLO P-11-B-07 · Understanding

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89. A gyroscope keeps its axis pointing in a fixed direction because:

  1. friction holds it
  2. its large angular momentum resists changes in direction
  3. it has no mass
  4. gravity is zero

Answer: B) its large angular momentum resists changes in direction

Explanation: Changing vecL needs a torque. SLO P-11-B-20 · Application

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90. An ice skater with I = 2 kg m^2 spins at 10 rad/s, then pulls in her arms so I = 5 kg m^2. Her new angular velocity is:

  1. 8 rad/s
  2. 25 rad/s
  3. 4 rad/s
  4. 2 rad/s

Answer: C) 4 rad/s

Explanation: I1omega1 = I2omega2 Rightarrow omega2 = 2 105 = 4 rad/s. SLO P-11-B-20 · Application

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91. An ice skater with I = 6 kg m^2 spins at 3 rad/s, then pulls in her arms so I = 2 kg m^2. Her new angular velocity is:

  1. 9 rad/s
  2. 4.5 rad/s
  3. 18 rad/s
  4. 1 rad/s

Answer: A) 9 rad/s

Explanation: I1omega1 = I2omega2 Rightarrow omega2 = 6 32 = 9 rad/s. SLO P-11-B-20 · Application

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92. If the radius is doubled at the same speed, the centripetal force becomes:

  1. twice as large
  2. 4 times as large
  3. half as large
  4. unchanged

Answer: C) half as large

Explanation: F propto 1/r. SLO P-11-B-14 · Application

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93. Angular momentum is conserved when:

  1. no external torque acts
  2. the body is at rest
  3. no external force acts
  4. kinetic energy is conserved

Answer: A) no external torque acts

Explanation: tau = Delta LDelta t; zero torque means constant L. SLO P-11-B-20 · Application

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94. Cream is separated from milk in a dairy centrifuge because:

  1. cream is less dense and stays nearer the axis
  2. cream is magnetic
  3. cream boils faster
  4. cream is denser

Answer: A) cream is less dense and stays nearer the axis

Explanation: Lighter components move inward relative to denser ones. SLO P-11-B-21 · Application

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95. At the axis of a rotating space station, an astronaut would feel:

  1. pulled outward strongly
  2. double gravity
  3. full Earth gravity
  4. weightless

Answer: D) weightless

Explanation: r = 0 Rightarrow a = 0. SLO P-11-B-17 · Understanding

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96. The Earth's angular momentum about its axis stays nearly constant because:

  1. it is not rotating
  2. gravity keeps it constant
  3. it has no mass
  4. external torques on it are very small

Answer: D) external torques on it are very small

Explanation: Hence the steady length of the day. SLO P-11-B-20 · Application

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97. A fan running at 30 rad/s is switched off and stops uniformly in 10 s. The number of revolutions it makes while stopping is about:

  1. 4.8
  2. 47.7
  3. 150
  4. 23.9

Answer: D) 23.9

Explanation: theta = omegai + omegaf2t = 15 10 = 150 rad = 1502pi approx 23.9 rev. SLO P-11-B-09 · Application

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98. The ideal banking angle of a curve with r = 100 m for v = 20 m/s (g = 10) satisfies tantheta =

  1. 0.4
  2. 0.2
  3. 4
  4. 2.5

Answer: A) 0.4

Explanation: tantheta = v^2rg = 4001000 = 0.4. SLO P-11-B-15 · Application

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99. One complete revolution equals:

  1. 2pi rad
  2. pi rad
  3. 1 rad
  4. 360 rad

Answer: A) 2pi rad

Explanation: 360^circ = 2pi rad. SLO P-11-B-07 · Understanding

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100. 180^circ expressed in radians is:

  1. pi
  2. 2pi
  3. 3pi
  4. pi2

Answer: A) pi

Explanation: Multiply by pi180^circ: 180 pi180 = pi rad. SLO P-11-B-07 · Understanding

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