MCQs / Physics / Current Electricity
Current Electricity MCQs — Physics (page 8) 270 multiple-choice questions on Current Electricity from Physics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.
176. A charge of 0.5 C moves through a p.d. of 230 V. The energy transferred is: 230 J 460 J 115 J 57.5 J Answer: C) 115 J
Explanation: W = QV = 115 J. SLO P-09-E-11 · Application
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177. Resistors of 4 Ω, 4 Ω, 4 Ω, 4 Ω are connected in series. The combined resistance is: 32 Ω 160 Ω 8 Ω 16 Ω Answer: D) 16 Ω
Explanation: R = R1 + R2 + ldots = 16 Ω. SLO P-09-E-20 · Application
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178. A wire has resistivity 1.1 10^-6 Ω m, length 0.5 m and cross-section 2 10^-7 m^2. Its resistance is: 2.75 Ω 0.275 Ω 27.5 Ω 5.5 Ω Answer: A) 2.75 Ω
Explanation: R = rho LA = 2.75 Ω. SLO P-09-E-13 · Application
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179. At a junction, currents of 2.5 A flow in. Currents of 1.2 A, 0.3 A flow out, together with one unknown current I. I is: 2 A 0.5 A 1 A 10 A Answer: C) 1 A
Explanation: sum Iin = sum Iout Rightarrow I = 2.5 - 1.5 = 1 A. SLO P-09-E-18 · Knowledge
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180. A 6 V battery is connected across three 2 Ω resistors in parallel. The battery current is: 0.67 A 9 A 1 A 3 A Answer: B) 9 A
Explanation: Each branch 3 A. SLO P-09-E-22 · Application
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181. A potentiometer wire is 1 m long with 2 V across it. The potential gradient is: 200 V/m 2 V/cm 0.5 V/m 2 V/m Answer: D) 2 V/m
Explanation: k = V/L. SLO P-09-E-23 · Application
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182. A 12 V cell with negligible internal resistance is connected to a 4 Ω resistor in series with a parallel pair of 6 Ω and 3 Ω. The current from the cell is: 2 A 3 A 1 A 0.92 A Answer: A) 2 A
Explanation: Parallel pair = 2 Ω; total = 6 Ω; I = 12/6. SLO P-09-E-22 · Application
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183. A circuit has a 9 V cell, internal resistance 1 Ω, and an external 8 Ω resistor. The current is: 1 A 9 A 0.89 A 1.125 A Answer: A) 1 A
Explanation: I = 98 + 1. SLO P-09-E-22 · Application
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184. When a car's starter motor is operated, the headlights dim because: the headlights are disconnected the motor produces light the battery's e.m.f. increases the large current causes a big p.d. across the battery's internal resistance Answer: D) the large current causes a big p.d. across the battery's internal resistance
Explanation: Terminal p.d. drops. SLO P-09-E-26 · Understanding
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185. A cell of e.m.f. 1.5 V and internal resistance 0.5 Ω is connected to a 2.5 Ω resistor. The terminal p.d. is: 0.625 V 1.25 V 2.5 V 12.5 V Answer: B) 1.25 V
Explanation: I = mathcalER + r = 0.5 A; V = IR = 1.25 V (lost volts Ir = 0.25 V). SLO P-09-E-17 · Understanding
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186. Adding another resistor in series to a circuit makes the current: increase stay the same decrease reverse Answer: C) decrease
Explanation: Total resistance increases. SLO P-09-E-20 · Application
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187. Ordinary concrete without fibres is a: poor conductor of electricity good conductor magnet superconductor Answer: A) poor conductor of electricity
Explanation: Fibres provide the conducting path. SLO P-09-E-27 · Understanding
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188. A 3 Ω resistor is connected to 9 V. The power is: 27 W 28 W 3 W 54 W Answer: A) 27 W
Explanation: P = V^2R = 9^23 = 27 W. SLO P-09-E-12 · Application
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189. Measuring resistance to detect damage is useful because it: needs the bridge to be closed for months is quick and doesn't need the bridge to be broken open requires removing the concrete needs X-ray equipment Answer: B) is quick and doesn't need the bridge to be broken open
Explanation: Non-destructive testing. SLO P-09-E-27 · Understanding
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190. A current of 10 A flows through a 0.5 Ω resistor. The power dissipated is: 100 W 5 W 25 W 50 W Answer: D) 50 W
Explanation: P = I^2R = (10)^2(0.5) = 50 W. SLO P-09-E-12 · Application
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191. A generator produces e.m.f. by converting: mechanical energy into electrical energy electrical into mechanical heat into chemical energy light into sound Answer: A) mechanical energy into electrical energy
Explanation: Energy input to charges. SLO P-09-E-16 · Understanding
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192. Embedding sensors in structures for continuous checking is called: power generation radio broadcasting structural health monitoring electroplating Answer: C) structural health monitoring
Explanation: Engineering application. SLO P-09-E-27 · Understanding
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193. In I = Anvq, n stands for: the number of turns the number of electrons in the wire the refractive index the number of charge carriers per unit volume Answer: D) the number of charge carriers per unit volume
Explanation: Units m^-3. SLO P-09-E-10 · Application
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194. Two cells, 6 V and 4 V, are connected in series opposing with a 5 Ω resistor. The current is: 0.4 A 1.2 A 2 A 0.8 A Answer: A) 0.4 A
Explanation: Net e.m.f. = 2 V; I = 2/5. SLO P-09-E-22 · Application
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195. Two identical cells in parallel compared with one cell give: the same e.m.f. but half the internal resistance double the e.m.f. double the internal resistance zero e.m.f. Answer: A) the same e.m.f. but half the internal resistance
Explanation: Parallel internal resistances. SLO P-09-E-26 · Understanding
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196. The potential difference between two points is: the current per unit time the energy transferred per unit charge passing between them the charge per unit energy the force per unit charge Answer: B) the energy transferred per unit charge passing between them
Explanation: V = W/Q. SLO P-09-E-11 · Application
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197. A 24 V supply drives current through 3 Ω and R in series; the current is 2 A. R is: 12 Ω 9 Ω 6 Ω 3 Ω Answer: B) 9 Ω
Explanation: Total = 12 Ω. SLO P-09-E-22 · Application
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198. A current of 5 A flows in a wire with n = 8.5 10^28 m^-3 and area 3 10^-6 m^2. The drift velocity of the electrons is: 1.23 10^-4 m/s 2.45 10^-4 m/s 0.00123 m/s 1.23 10^-5 m/s Answer: A) 1.23 10^-4 m/s
Explanation: v = InAq = 1.23 10^-4 m/s — very slow. SLO P-09-E-10 · Application
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199. Taking currents into a junction as positive, Kirchhoff's first law can be written as: sum I = 0 sum IR = sum mathcalE sum I = 1 sum V = 0 Answer: A) sum I = 0
Explanation: Algebraic sum. SLO P-09-E-18 · Knowledge
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200. Which instrument uses a galvanometer in a null method? a thermometer a voltmeter across a lamp a potentiometer an ammeter in series Answer: C) a potentiometer
Explanation: Balance with zero current. SLO P-09-E-24 · Understanding
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