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Heat Engines, Second Law and Entropy MCQs — Physics (page 3)

165 multiple-choice questions on Heat Engines, Second Law and Entropy from Physics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.

51. When a substance is heated, the disorder of its particles:

  1. stays the same
  2. increases
  3. becomes zero
  4. decreases

Answer: B) increases

Explanation: Particles move more randomly. SLO P-11-C-18 · Understanding

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52. A real engine is less efficient than a Carnot engine because:

  1. it uses a different gas
  2. it needs no reservoirs
  3. it is larger
  4. real processes are irreversible (friction, heat losses)

Answer: D) real processes are irreversible (friction, heat losses)

Explanation: Losses. SLO P-11-C-16 · Understanding

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53. Perfume released in one corner of a room soon fills it because:

  1. air pushes it in one direction
  2. molecules spread randomly into the most probable (disordered) state
  3. it is lighter than air
  4. it is attracted to walls

Answer: B) molecules spread randomly into the most probable (disordered) state

Explanation: Diffusion increases entropy. SLO P-11-C-21 · Understanding

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54. To reduce the disorder of a system, we must:

  1. isolate it
  2. do work on it, increasing disorder elsewhere
  3. wait
  4. cool the universe

Answer: B) do work on it, increasing disorder elsewhere

Explanation: e.g. tidying a room uses your energy. SLO P-11-C-21 · Understanding

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55. The maximum efficiency of a heat engine is given by:

  1. eta = 1 - TCTH
  2. eta = TH - TC
  3. eta = TCTH
  4. eta = 1 - THTC

Answer: A) eta = 1 - TCTH

Explanation: Carnot limit, temperatures in kelvin. SLO P-11-C-23 · Knowledge

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56. Doubling TH (in kelvin) with TC fixed:

  1. does not change the efficiency
  2. halves the efficiency
  3. increases the maximum efficiency
  4. makes it 100%

Answer: C) increases the maximum efficiency

Explanation: TC/TH gets smaller. SLO P-11-C-23 · Knowledge

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57. 1000 J of heat is added reversibly at 250 K. The entropy change is:

  1. 250,000 J/K
  2. 0.25 J/K
  3. 1250 J/K
  4. 4 J/K

Answer: D) 4 J/K

Explanation: Delta S = 1000/250. SLO P-11-C-18 · Understanding

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58. Why can't the heat from a cup of tea that has cooled be used to reheat it?

  1. the first law forbids it
  2. the energy was destroyed
  3. heat has no energy
  4. the energy is spread out at low temperature (degraded)

Answer: D) the energy is spread out at low temperature (degraded)

Explanation: It has become unavailable. SLO P-11-C-20 · Understanding

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59. A diesel engine ignites fuel by:

  1. a spark plug
  2. electricity only
  3. the heat of highly compressed air
  4. a flame

Answer: C) the heat of highly compressed air

Explanation: Compression ignition. SLO P-11-C-13 · Knowledge

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60. The increase in entropy when heat Q is added reversibly at temperature T is:

  1. Delta S = QT
  2. Delta S = QT
  3. Delta S = Q - T
  4. Delta S = TQ

Answer: B) Delta S = QT

Explanation: Unit J/K. SLO P-11-C-18 · Understanding

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61. A heat engine could be 100% efficient only if:

  1. both reservoirs were at the same temperature
  2. the cold reservoir were at absolute zero
  3. the hot reservoir were at 0 K
  4. there were no friction

Answer: B) the cold reservoir were at absolute zero

Explanation: Impossible in practice. SLO P-11-C-23 · Knowledge

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62. The Kelvin–Planck statement of the second law says:

  1. no engine working in a cycle can convert all the heat it takes in into work
  2. energy is conserved
  3. entropy decreases
  4. heat flows from cold to hot

Answer: A) no engine working in a cycle can convert all the heat it takes in into work

Explanation: Some heat must be rejected. SLO P-11-C-15 · Understanding

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63. Slowly compressing a gas in a frictionless cylinder in contact with a heat bath is:

  1. close to reversible
  2. strongly irreversible
  3. impossible
  4. explosive

Answer: A) close to reversible

Explanation: Quasi-static isothermal change. SLO P-11-C-14 · Understanding

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64. A temperature difference between two bodies is useful because:

  1. it makes mass
  2. it allows a heat engine to do work
  3. it destroys energy
  4. it increases entropy

Answer: B) it allows a heat engine to do work

Explanation: Once equalised, no work can be extracted. SLO P-11-C-19 · Understanding

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65. A refrigerator does not violate the second law because:

  1. heat flows naturally from cold to hot
  2. it has 100% efficiency
  3. work is done on it to move heat from cold to hot
  4. it creates cold

Answer: C) work is done on it to move heat from cold to hot

Explanation: External work is supplied. SLO P-11-C-15 · Understanding

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66. Which of these is irreversible?

  1. an ideal Carnot cycle
  2. heat flowing from a hot body to a cold one
  3. a very slow, frictionless compression of a gas
  4. a quasi-static isothermal expansion

Answer: B) heat flowing from a hot body to a cold one

Explanation: Heat never flows back by itself. SLO P-11-C-14 · Understanding

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67. Heat Q flows from a hot body at TH to a cold body at TC. The total entropy change is:

  1. Q(TH - TC)
  2. 0
  3. QTC - QTH 0
  4. QTH - QTC 0

Answer: C) QTC - QTH 0

Explanation: Cold body gains more entropy than the hot body loses. SLO P-11-C-22 · Understanding

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68. Gas released from a cylinder into a vacuum chamber:

  1. becomes liquid
  2. spreads to fill it and does not return
  3. returns to the cylinder
  4. stays in one corner

Answer: B) spreads to fill it and does not return

Explanation: Free expansion increases disorder. SLO P-11-C-21 · Understanding

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69. A falling raindrop at terminal velocity converts its gravitational potential energy into:

  1. kinetic energy
  2. chemical energy
  3. heat in the air (degraded energy)
  4. nuclear energy

Answer: C) heat in the air (degraded energy)

Explanation: Its KE is constant. SLO P-11-C-20 · Understanding

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70. The part of a refrigerator where the refrigerant evaporates and absorbs heat is the:

  1. evaporator (inside the fridge)
  2. condenser (back coils)
  3. thermostat
  4. compressor

Answer: A) evaporator (inside the fridge)

Explanation: Evaporation absorbs latent heat. SLO P-11-C-17 · Understanding

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71. When ice melts to water, the disorder of the molecules:

  1. stays the same
  2. is destroyed
  3. decreases
  4. increases

Answer: D) increases

Explanation: The regular lattice breaks down. SLO P-11-C-18 · Understanding

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72. Ocean water has a huge internal energy, but a ship can't run on it alone because:

  1. the energy is too small
  2. the first law forbids it
  3. water doesn't contain energy
  4. there is no colder reservoir to reject heat to

Answer: D) there is no colder reservoir to reject heat to

Explanation: Second law. SLO P-11-C-15 · Understanding

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73. Heat spreading through a metal rod until its temperature is uniform is an example of:

  1. work being created
  2. a reversible process
  3. a system becoming less orderly (entropy increasing)
  4. entropy decreasing

Answer: C) a system becoming less orderly (entropy increasing)

Explanation: Energy spreads out. SLO P-11-C-21 · Understanding

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74. When hot and cold water mix, the total energy is unchanged but:

  1. energy is destroyed
  2. entropy decreases
  3. entropy increases and the ability to do work is lost
  4. the water heats up more

Answer: C) entropy increases and the ability to do work is lost

Explanation: The temperature difference is gone. SLO P-11-C-19 · Understanding

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75. A heat engine:

  1. converts all heat into work
  2. creates energy
  3. takes heat from a hot reservoir, converts part into work and rejects the rest to a cold reservoir
  4. moves heat from cold to hot

Answer: C) takes heat from a hot reservoir, converts part into work and rejects the rest to a cold reservoir

Explanation: Basic principle. SLO P-11-C-13 · Knowledge

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