MCQs / Physics / Heat Engines, Second Law and Entropy
Heat Engines, Second Law and Entropy MCQs — Physics (page 3) 165 multiple-choice questions on Heat Engines, Second Law and Entropy from Physics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.
51. When a substance is heated, the disorder of its particles: stays the same increases becomes zero decreases Answer: B) increases
Explanation: Particles move more randomly. SLO P-11-C-18 · Understanding
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52. A real engine is less efficient than a Carnot engine because: it uses a different gas it needs no reservoirs it is larger real processes are irreversible (friction, heat losses) Answer: D) real processes are irreversible (friction, heat losses)
Explanation: Losses. SLO P-11-C-16 · Understanding
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53. Perfume released in one corner of a room soon fills it because: air pushes it in one direction molecules spread randomly into the most probable (disordered) state it is lighter than air it is attracted to walls Answer: B) molecules spread randomly into the most probable (disordered) state
Explanation: Diffusion increases entropy. SLO P-11-C-21 · Understanding
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54. To reduce the disorder of a system, we must: isolate it do work on it, increasing disorder elsewhere wait cool the universe Answer: B) do work on it, increasing disorder elsewhere
Explanation: e.g. tidying a room uses your energy. SLO P-11-C-21 · Understanding
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55. The maximum efficiency of a heat engine is given by: eta = 1 - TCTH eta = TH - TC eta = TCTH eta = 1 - THTC Answer: A) eta = 1 - TCTH
Explanation: Carnot limit, temperatures in kelvin. SLO P-11-C-23 · Knowledge
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56. Doubling TH (in kelvin) with TC fixed: does not change the efficiency halves the efficiency increases the maximum efficiency makes it 100% Answer: C) increases the maximum efficiency
Explanation: TC/TH gets smaller. SLO P-11-C-23 · Knowledge
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57. 1000 J of heat is added reversibly at 250 K. The entropy change is: 250,000 J/K 0.25 J/K 1250 J/K 4 J/K Answer: D) 4 J/K
Explanation: Delta S = 1000/250. SLO P-11-C-18 · Understanding
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58. Why can't the heat from a cup of tea that has cooled be used to reheat it? the first law forbids it the energy was destroyed heat has no energy the energy is spread out at low temperature (degraded) Answer: D) the energy is spread out at low temperature (degraded)
Explanation: It has become unavailable. SLO P-11-C-20 · Understanding
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59. A diesel engine ignites fuel by: a spark plug electricity only the heat of highly compressed air a flame Answer: C) the heat of highly compressed air
Explanation: Compression ignition. SLO P-11-C-13 · Knowledge
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60. The increase in entropy when heat Q is added reversibly at temperature T is: Delta S = QT Delta S = QT Delta S = Q - T Delta S = TQ Answer: B) Delta S = QT
Explanation: Unit J/K. SLO P-11-C-18 · Understanding
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61. A heat engine could be 100% efficient only if: both reservoirs were at the same temperature the cold reservoir were at absolute zero the hot reservoir were at 0 K there were no friction Answer: B) the cold reservoir were at absolute zero
Explanation: Impossible in practice. SLO P-11-C-23 · Knowledge
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62. The Kelvin–Planck statement of the second law says: no engine working in a cycle can convert all the heat it takes in into work energy is conserved entropy decreases heat flows from cold to hot Answer: A) no engine working in a cycle can convert all the heat it takes in into work
Explanation: Some heat must be rejected. SLO P-11-C-15 · Understanding
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63. Slowly compressing a gas in a frictionless cylinder in contact with a heat bath is: close to reversible strongly irreversible impossible explosive Answer: A) close to reversible
Explanation: Quasi-static isothermal change. SLO P-11-C-14 · Understanding
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64. A temperature difference between two bodies is useful because: it makes mass it allows a heat engine to do work it destroys energy it increases entropy Answer: B) it allows a heat engine to do work
Explanation: Once equalised, no work can be extracted. SLO P-11-C-19 · Understanding
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65. A refrigerator does not violate the second law because: heat flows naturally from cold to hot it has 100% efficiency work is done on it to move heat from cold to hot it creates cold Answer: C) work is done on it to move heat from cold to hot
Explanation: External work is supplied. SLO P-11-C-15 · Understanding
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66. Which of these is irreversible? an ideal Carnot cycle heat flowing from a hot body to a cold one a very slow, frictionless compression of a gas a quasi-static isothermal expansion Answer: B) heat flowing from a hot body to a cold one
Explanation: Heat never flows back by itself. SLO P-11-C-14 · Understanding
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67. Heat Q flows from a hot body at TH to a cold body at TC. The total entropy change is: Q(TH - TC) 0 QTC - QTH 0 QTH - QTC 0 Answer: C) QTC - QTH 0
Explanation: Cold body gains more entropy than the hot body loses. SLO P-11-C-22 · Understanding
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68. Gas released from a cylinder into a vacuum chamber: becomes liquid spreads to fill it and does not return returns to the cylinder stays in one corner Answer: B) spreads to fill it and does not return
Explanation: Free expansion increases disorder. SLO P-11-C-21 · Understanding
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69. A falling raindrop at terminal velocity converts its gravitational potential energy into: kinetic energy chemical energy heat in the air (degraded energy) nuclear energy Answer: C) heat in the air (degraded energy)
Explanation: Its KE is constant. SLO P-11-C-20 · Understanding
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70. The part of a refrigerator where the refrigerant evaporates and absorbs heat is the: evaporator (inside the fridge) condenser (back coils) thermostat compressor Answer: A) evaporator (inside the fridge)
Explanation: Evaporation absorbs latent heat. SLO P-11-C-17 · Understanding
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71. When ice melts to water, the disorder of the molecules: stays the same is destroyed decreases increases Answer: D) increases
Explanation: The regular lattice breaks down. SLO P-11-C-18 · Understanding
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72. Ocean water has a huge internal energy, but a ship can't run on it alone because: the energy is too small the first law forbids it water doesn't contain energy there is no colder reservoir to reject heat to Answer: D) there is no colder reservoir to reject heat to
Explanation: Second law. SLO P-11-C-15 · Understanding
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73. Heat spreading through a metal rod until its temperature is uniform is an example of: work being created a reversible process a system becoming less orderly (entropy increasing) entropy decreasing Answer: C) a system becoming less orderly (entropy increasing)
Explanation: Energy spreads out. SLO P-11-C-21 · Understanding
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74. When hot and cold water mix, the total energy is unchanged but: energy is destroyed entropy decreases entropy increases and the ability to do work is lost the water heats up more Answer: C) entropy increases and the ability to do work is lost
Explanation: The temperature difference is gone. SLO P-11-C-19 · Understanding
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75. A heat engine: converts all heat into work creates energy takes heat from a hot reservoir, converts part into work and rejects the rest to a cold reservoir moves heat from cold to hot Answer: C) takes heat from a hot reservoir, converts part into work and rejects the rest to a cold reservoir
Explanation: Basic principle. SLO P-11-C-13 · Knowledge
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