MCQs / Physics / Heat Engines, Second Law and Entropy
Heat Engines, Second Law and Entropy MCQs — Physics (page 4) 165 multiple-choice questions on Heat Engines, Second Law and Entropy from Physics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.
76. 600 J flows from a body at 600 K to one at 300 K. The total entropy change is: +3 J/K 0 J/K +1 J/K -1 J/K Answer: C) +1 J/K
Explanation: 600300 - 600600 = 2 - 1 = 1 J/K. SLO P-11-C-22 · Understanding
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77. A refrigerator removes 900 J from its contents using 300 J of electrical work. The heat given out to the kitchen is: 1200 J 300 J 900 J 600 J Answer: A) 1200 J
Explanation: QH = QC + W = 1200 J. SLO P-11-C-17 · Understanding
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78. The unit of entropy is: J/K J K W Answer: A) J/K
Explanation: Delta S = Q/T. SLO P-11-C-19 · Understanding
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79. A pendulum swinging in air gradually stops; this shows the process is: reversible cyclic and reversible irreversible isothermal Answer: C) irreversible
Explanation: Air drag dissipates energy. SLO P-11-C-14 · Understanding
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80. A gas expanding freely into a vacuum is: irreversible adiabatic and reversible quasi-static reversible Answer: A) irreversible
Explanation: It never re-compresses by itself. SLO P-11-C-14 · Understanding
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81. A drop of ink in water spreads out because: ink molecules repel each other strongly the water heats the ink ink is pushed by water the spread-out state is far more probable Answer: D) the spread-out state is far more probable
Explanation: Entropy increases. SLO P-11-C-21 · Understanding
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82. An engine that turns all its heat into work would violate: the first law Newton's third law the zeroth law the second law of thermodynamics Answer: D) the second law of thermodynamics
Explanation: Perpetual motion of the second kind. SLO P-11-C-15 · Understanding
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83. A heat engine takes in 800 J from the hot reservoir and rejects 200 J to the cold reservoir. Its efficiency is: 25% 37.5% 75% 80% Answer: C) 75%
Explanation: W = QH - QC = 600 J; eta = WQH = 75%. SLO P-11-C-13 · Knowledge
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84. A claim that an engine working between 400 K and 300 K has 40% efficiency is: below the limit possible exactly the Carnot value impossible — the maximum is 25% Answer: D) impossible — the maximum is 25%
Explanation: 1 - 300/400 = 0.25. SLO P-11-C-23 · Knowledge
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85. A heat engine takes in 1000 J from the hot reservoir and rejects 600 J to the cold reservoir. Its efficiency is: 60% 62.5% 40% 20% Answer: C) 40%
Explanation: W = QH - QC = 400 J; eta = WQH = 40%. SLO P-11-C-13 · Knowledge
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86. Ice cubes in a warm drink melt rather than grow because: it decreases entropy this increases the total entropy of gravity energy is destroyed Answer: B) this increases the total entropy
Explanation: Natural direction. SLO P-11-C-21 · Understanding
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87. The SI unit of entropy is: K J^-1 J K^-1 J J s Answer: B) J K^-1
Explanation: From Delta S = Q/T. SLO P-11-C-22 · Understanding
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88. Which factor makes a process irreversible? slow change no heat transfer friction equilibrium at each step Answer: C) friction
Explanation: Energy is dissipated as heat. SLO P-11-C-14 · Understanding
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89. Although energy is conserved, we speak of an 'energy crisis' because: temperature is falling useful energy is degraded into heat that can't easily be used the first law fails energy is destroyed Answer: B) useful energy is degraded into heat that can't easily be used
Explanation: Second law. SLO P-11-C-19 · Understanding
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90. When food is digested, chemical energy is ultimately degraded to: potential energy stored forever mass body heat lost to the surroundings nuclear energy Answer: C) body heat lost to the surroundings
Explanation: Living things also obey the second law. SLO P-11-C-20 · Understanding
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91. 'Time's arrow' (the one-way direction of time) is linked to: Newton's first law the speed of light the increase of entropy conservation of energy Answer: C) the increase of entropy
Explanation: We see disorder increase with time. SLO P-11-C-21 · Understanding
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92. Melting of ice at exactly 0 °C with heat supplied infinitely slowly is: explosive impossible highly irreversible approximately reversible Answer: D) approximately reversible
Explanation: A tiny change in temperature would reverse it. SLO P-11-C-14 · Understanding
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93. In all natural (real) processes, the total entropy of the universe: stays the same becomes zero decreases increases Answer: D) increases
Explanation: Second law. SLO P-11-C-20 · Understanding
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94. When a gas expands isothermally, its entropy: becomes zero increases stays constant decreases Answer: B) increases
Explanation: More space, more arrangements. SLO P-11-C-22 · Understanding
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95. The work done by a heat engine in one cycle is: W = QH QC W = QH - QC W = QC - QH W = QH + QC Answer: B) W = QH - QC
Explanation: Energy conservation. SLO P-11-C-13 · Knowledge
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96. A gas has more entropy than a solid of the same substance because: it has fewer particles its particles have many more possible positions and speeds it is heavier it is colder Answer: B) its particles have many more possible positions and speeds
Explanation: More microstates. SLO P-11-C-22 · Understanding
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97. The Carnot engine is important because: it is used in all cars it has 100% efficiency it needs no cold reservoir no engine working between the same two temperatures can be more efficient Answer: D) no engine working between the same two temperatures can be more efficient
Explanation: Carnot's theorem. SLO P-11-C-16 · Understanding
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98. Heating a solid makes its atoms: line up more neatly stop vibrating vibrate more randomly about their positions lose mass Answer: C) vibrate more randomly about their positions
Explanation: More thermal disorder. SLO P-11-C-18 · Understanding
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99. The same amount of heat produces a larger increase in disorder when added to a: hot body body at any temperature equally body at infinite temperature cold body Answer: D) cold body
Explanation: Delta S = Q/T; small T gives large Delta S. SLO P-11-C-18 · Understanding
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100. The maximum possible efficiency of an engine working between 127 °C and 27 °C is: 25% 78.7% 75% 50% Answer: A) 25%
Explanation: Convert to kelvin: TH = 400 K, TC = 300 K. etamax = 1 - 300400 = 25%. SLO P-11-C-23 · Knowledge
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