MCQs / Physics / Deformation of Solids
Deformation of Solids MCQs — Physics (page 2) 110 multiple-choice questions on Deformation of Solids from Physics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.
26. Why is the work done for a Hooke's-law spring 12Fe and not Fe? Fe is the momentum the spring only moves half the distance half the energy is lost as heat the force rises from zero to F, so the average force is F2 Answer: D) the force rises from zero to F, so the average force is F2
Explanation: Work = average force × extension. SLO P-11-B-27 · Application
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27. A spring's force rises linearly from 10 N at extension 0.02 m to 30 N at 0.06 m. The work done over this range is: 1.6 J 0.8 J 0.4 J 1.2 J Answer: B) 0.8 J
Explanation: Area of the trapezium = 12(10 + 30)(0.06 - 0.02) = 0.8 J. SLO P-11-B-27 · Application
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28. A spring of spring constant 50 N/m is stretched by 0.3 m (within the limit of proportionality). The elastic potential energy stored is: 4.5 J 2.25 J 1.12 J 7.5 J Answer: B) 2.25 J
Explanation: Ep = 12kx^2 = 12(50)(0.3)^2 = 2.25 J. SLO P-11-B-28 · Application
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29. For a non-linear force–extension graph, the work done is found by: dividing the force by extension multiplying the final force by the extension estimating the area under the curve (e.g. counting squares) using 12Fe always Answer: C) estimating the area under the curve (e.g. counting squares)
Explanation: The triangle formula only works for a straight line. SLO P-11-B-27 · Application
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30. The basic repeating unit of a crystal lattice is called the: molecule chain grain boundary monomer unit cell Answer: D) unit cell
Explanation: The lattice is built by repeating the unit cell. SLO P-11-B-22 · Understanding
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31. Two springs are stretched by the same force. The one with the larger extension stores: no energy the same energy less energy more energy Answer: D) more energy
Explanation: W = 12Fe. SLO P-11-B-27 · Application
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32. Stress is defined as: stress/strain force per unit cross-sectional area extension per unit length force × extension Answer: B) force per unit cross-sectional area
Explanation: sigma = F/A, unit pascal. SLO P-11-B-24 · Application
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33. In the experiment, the load is increased: until the wire breaks first in equal steps, recording the extension each time all at once randomly Answer: B) in equal steps, recording the extension each time
Explanation: This gives a series of points for a graph. SLO P-11-B-25 · Understanding
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34. An amorphous (glassy) solid, when heated: turns directly into gas never softens softens gradually over a range of temperatures melts sharply at one temperature Answer: C) softens gradually over a range of temperatures
Explanation: Bonds have different strengths. SLO P-11-B-22 · Understanding
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35. A toy gun's spring (k = 200 N/m) is compressed 0.1 m and launches a 50 g ball. Ignoring losses, the ball's speed is: 8.94 m/s 12.6 m/s 6.32 m/s 3.16 m/s Answer: C) 6.32 m/s
Explanation: 12kx^2 = 12mv^2 Rightarrow v = x km = 6.32 m/s. SLO P-11-B-28 · Application
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36. Polymers are made of: ions in a regular array free electrons only long chain molecules built from repeating units (monomers) single atoms in a cubic lattice Answer: C) long chain molecules built from repeating units (monomers)
Explanation: e.g. polythene: repeated CH2 units. SLO P-11-B-22 · Understanding
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37. A ductile material such as copper: has no elastic region can be drawn into wires (shows large plastic deformation) is amorphous breaks without deforming Answer: B) can be drawn into wires (shows large plastic deformation)
Explanation: Ductile = can be drawn out. SLO P-11-B-26 · Understanding
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38. A wire of length 3 m and cross-section 5 10^-6 m^2 extends by 3 mm under 1000 N. The Young modulus is: 2 10^11 Pa 4 10^11 Pa 2 10^10 Pa 2 10^12 Pa Answer: A) 2 10^11 Pa
Explanation: Y = F/Ae/l = FlAe = 2 10^11 Pa. SLO P-11-B-24 · Application
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39. A spring of constant 400 N/m stores 2 J of elastic energy. Its extension is: 0.01 m 0.2 m 0.1 m 0.05 m Answer: C) 0.1 m
Explanation: x = 2Ek = 2(2)400 = 0.1 m. SLO P-11-B-28 · Application
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40. A spring obeying Hooke's law extends 0.4 cm under a final force of 250 N. The work done in stretching it is: 0.25 J 1 J 50 J 0.5 J Answer: D) 0.5 J
Explanation: Work = area of the triangle = 12Fe = 12(250)(0.004) = 0.5 J. SLO P-11-B-27 · Application
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41. A graph of force (N) against extension (m) has area 0.5 N m. The energy stored is: 5 J 50 J 0.5 J 0.05 J Answer: C) 0.5 J
Explanation: N m = J. SLO P-11-B-27 · Application
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42. Ep = 12Fx and Ep = 12kx^2 are equivalent because: F = kx^2 F = kx k = Fx F = 12kx Answer: B) F = kx
Explanation: Substitute Hooke's law. SLO P-11-B-28 · Application
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43. A spring of spring constant 800 N/m is stretched by 0.05 m (within the limit of proportionality). The elastic potential energy stored is: 20 J 2 J 1 J 0.5 J Answer: C) 1 J
Explanation: Ep = 12kx^2 = 12(800)(0.05)^2 = 1 J. SLO P-11-B-28 · Application
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44. When a solid is compressed, the atoms: stop vibrating move further apart are destroyed are pushed closer and repel each other Answer: D) are pushed closer and repel each other
Explanation: Repulsive forces resist compression. SLO P-11-B-23 · Understanding
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45. In one-dimensional deformation, the change in the length of a wire is called the: stress strain energy extension Young modulus Answer: C) extension
Explanation: Extension e = l - l0. SLO P-11-B-23 · Understanding
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46. Which of these is a crystalline solid? rubber glass sodium chloride (common salt) polythene Answer: C) sodium chloride (common salt)
Explanation: Salt forms cubic crystals. SLO P-11-B-22 · Understanding
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47. A force that squashes a pillar produces: no deformation torsion tensile deformation compressive deformation Answer: D) compressive deformation
Explanation: Compression decreases the length. SLO P-11-B-23 · Understanding
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48. A compression spring in a car's suspension: gets longer under load breaks at once gets shorter under load keeps its length Answer: C) gets shorter under load
Explanation: It is compressed. SLO P-11-B-23 · Understanding
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49. A catapult converts elastic potential energy into: kinetic energy of the stone chemical energy nuclear energy only heat Answer: A) kinetic energy of the stone
Explanation: Energy conservation. SLO P-11-B-28 · Application
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50. A spring with k = 200 N/m is stretched 0.1 m. The area under its force–extension graph is: 10 J 20 J 1 J 2 J Answer: C) 1 J
Explanation: 12(200)(0.1)^2 = 1 J. SLO P-11-B-27 · Application
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