MCQs / Physics / Kinetic Theory and First Law of Thermodynamics
Kinetic Theory and First Law of Thermodynamics MCQs — Physics (page 3) 180 multiple-choice questions on Kinetic Theory and First Law of Thermodynamics from Physics, each with the correct answer and, where available, a teacher's explanation. Read through them to revise the chapter, then practise the same questions one by one to test yourself.
51. Using R = 8.31 and NA = 6.02 10^23, k works out to: 5.00 10^24 J/K 1.38 10^-23 J/K 1.38 10^23 J/K 7.24 10^22 J/K Answer: B) 1.38 10^-23 J/K
Explanation: 8.316.02 10^23 = 1.38 10^-23. SLO P-11-C-04 · Knowledge
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52. The molar gas constant R has the unit: N m^-2 J K^-1 J mol^-1 K^-1 J mol^-1 Answer: C) J mol^-1 K^-1
Explanation: R = pVnT. SLO P-11-C-03 · Application
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53. 1 mol of an ideal gas at 273 K occupies 0.0224 m^3. Its pressure is (R = 8.31 J mol^-1 K^-1): 1.01 10^5 Pa 10,100 Pa 1.01 10^6 Pa 2.03 10^5 Pa Answer: A) 1.01 10^5 Pa
Explanation: P = nRTV = 1 8.31 2730.0224 = 1.01 10^5 Pa. SLO P-11-C-03 · Application
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54. Boyle's law states that at constant temperature: p propto T p propto 1V V propto T p propto V Answer: B) p propto 1V
Explanation: pV = constant. SLO P-11-C-09 · Understanding
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55. Charles's law states that at constant pressure: p propto V pV = 0 V propto 1T V propto T Answer: D) V propto T
Explanation: With T in kelvin. SLO P-11-C-09 · Understanding
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56. 1 mol of an ideal gas is heated at constant pressure so its temperature rises by 100 K. The work done by the gas is: 416 J 1660 J 1250 J 831 J Answer: D) 831 J
Explanation: W = pDelta V = nRDelta T = 1 8.31 100 = 831 J. SLO P-11-C-06 · Application
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57. The internal energy of a gas decreases by 60 J while it does 40 J of work. The heat supplied to it is: (Use Q = Delta U + W, where Q = heat supplied to the gas and W = work done by the gas.) -200 J -10 J -40 J -20 J Answer: D) -20 J
Explanation: Q = Delta U + W = -60 + 40 = -20 J. (Negative: heat flows out.) SLO P-11-C-08 · Application
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58. Kinetic theory assumes that between collisions the molecules: move in straight lines at constant speed (no intermolecular forces) are at rest move in circles attract each other Answer: A) move in straight lines at constant speed (no intermolecular forces)
Explanation: Forces act only during collisions. SLO P-11-C-05 · Understanding
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59. A balloon taken from a warm room into a cold freezer: keeps the same size expands bursts shrinks Answer: D) shrinks
Explanation: Lower T, slower molecules, less volume needed at the same pressure. SLO P-11-C-09 · Understanding
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60. Gas pressure is explained by kinetic theory as: heat flow the attraction between molecules the force per unit area from molecules colliding with the walls the weight of the gas Answer: C) the force per unit area from molecules colliding with the walls
Explanation: Rate of change of momentum at the walls. SLO P-11-C-05 · Understanding
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61. In the equivalent form Delta U = Q + Won, the term Won is: the work done by the system the heat lost the change in temperature the work done on the system Answer: D) the work done on the system
Explanation: Won = -Wby, so this matches Q = Delta U + Wby. SLO P-11-C-08 · Application
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62. A gas expands at a constant pressure of 10^5 Pa from 2 L to 6 L while absorbing 1000 J of heat. Its internal energy increases by: 600 J 1400 J 400 J 1000 J Answer: A) 600 J
Explanation: W = pDelta V = 400 J; Delta U = Q - W = 600 J. SLO P-11-C-08 · Application
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63. Ideal gas behaviour is a good approximation for a gas of: very low temperature near liquefaction high density solid particles low density Answer: D) low density
Explanation: Molecules far apart. SLO P-11-C-05 · Understanding
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64. At constant pressure, a gas expands when heated because: the container shrinks gravity weakens the molecules grow faster molecules need more space to keep the same collision rate per unit area Answer: D) faster molecules need more space to keep the same collision rate per unit area
Explanation: V ∝ T at constant p. SLO P-11-C-09 · Understanding
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65. When the volume of a gas does not change, the work done by it is: nRT maximum zero pV Answer: C) zero
Explanation: Delta V = 0. SLO P-11-C-06 · Application
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66. Rubbing your hands raises their temperature because: work done against friction increases internal energy blood cools heat flows from the air the hands lose mass Answer: A) work done against friction increases internal energy
Explanation: Work → internal energy. SLO P-11-C-02 · Understanding
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67. The kinetic theory assumes the number of molecules is: zero very large, so statistical averages can be used very small exactly one Answer: B) very large, so statistical averages can be used
Explanation: Averages are meaningful. SLO P-11-C-05 · Understanding
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68. In a cyclic process (gas returns to its initial state): net heat absorbed = net work done net heat is always zero net work is always zero internal energy increases Answer: A) net heat absorbed = net work done
Explanation: Delta U = 0 over a cycle. SLO P-11-C-11 · Application
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69. A fixed mass of gas at 1.5 10^5 Pa occupies 4 L. At constant temperature it is changed to 6 L. The new pressure is: 1 10^5 Pa 2 10^5 Pa 50,000 Pa 2.25 10^5 Pa Answer: A) 1 10^5 Pa
Explanation: p1V1 = p2V2 Rightarrow p2 = 1.5 10^5 46 = 1 10^5 Pa. SLO P-11-C-10 · Application
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70. The average translational kinetic energy of a gas molecule at 300 K is (k = 1.38 10^-23 J/K): 1.24 10^-20 J 4.14 10^-21 J 1.86 10^-20 J 6.21 10^-21 J Answer: D) 6.21 10^-21 J
Explanation: barEk = 32kT = 1.5 1.38 10^-23 300 = 6.21 10^-21 J. SLO P-11-C-02 · Understanding
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71. Two identical blocks, one at 20 °C and one at 60 °C. The block with greater internal energy is: impossible to say even though they are identical the block at 60 °C the block at 20 °C they are equal Answer: B) the block at 60 °C
Explanation: Same material and mass: higher temperature, more internal energy. SLO P-11-C-12 · Understanding
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72. Which gas is closest to ideal at room conditions? water vapour near boiling ammonia near liquefaction helium carbon dioxide at high pressure Answer: C) helium
Explanation: Small, weakly interacting atoms. SLO P-11-C-05 · Understanding
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73. The first law of thermodynamics is a form of the law of conservation of: momentum energy charge mass Answer: B) energy
Explanation: Energy in = increase stored + energy out. SLO P-11-C-08 · Application
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74. In Q = Delta U + W, Q is the heat supplied to the gas and W is: the power the weight the work done on the gas the work done by the gas Answer: D) the work done by the gas
Explanation: Energy supplied = increase in internal energy + work out. SLO P-11-C-08 · Application
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75. When a gas expands against a piston, work is done: by nobody by the gas on the surroundings on the gas by the surroundings only on the container walls Answer: B) by the gas on the surroundings
Explanation: The gas pushes the piston out. SLO P-11-C-07 · Understanding
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